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The major product obtained in the photo catalysed bromination of 2-methylbutane is:
- a)1-bromo-2-methylbutane
- b)1-bromo-3-methylbutane
- c)2-bromo-3-methylbutane
- d)2-bromo-2-methylbutane
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The major product obtained in the photo catalysed bromination of 2-met...
The photocatalyzed bromination of 2 − methylbutane proceeds via free radical mechanism. Since the stability of tertiary free radical is greater than that of primary and secondary radical, the major product obtained in the given reaction corresponds to that of tertiary free radical.
Thus, the major product formed in the given reaction is 2 − bromo − 2− methylbutane.
Thus, the major product formed in the given reaction is 2 − bromo − 2− methylbutane.
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The major product obtained in the photo catalysed bromination of 2-met...
Photo catalysed bromination of 2-methylbutane:
Photo catalysed bromination is a process in which light is used to activate a catalyst to initiate a chemical reaction. In this case, 2-methylbutane is brominated using a photo catalyst.
Reaction mechanism:
The reaction mechanism involves the following steps:
1. Initiation: The photo catalyst absorbs light and becomes excited, leading to the formation of free radicals.
2. Propagation: The free radicals react with the 2-methylbutane to form intermediate radicals.
3. Termination: The intermediate radicals react with each other to form the final product.
The major product obtained in the photo catalysed bromination of 2-methylbutane:
The major product obtained in the photo catalysed bromination of 2-methylbutane is 2-bromo-2-methylbutane (Option D).
Explanation:
When 2-methylbutane is brominated using a photo catalyst, the intermediate radical formed can undergo two different reactions:
1. Bromination at the primary carbon atom: In this case, the intermediate radical reacts with a bromine molecule to form 1-bromo-2-methylbutane (Option A) or 1-bromo-3-methylbutane (Option B).
2. Bromination at the tertiary carbon atom: In this case, the intermediate radical reacts with a bromine molecule to form 2-bromo-2-methylbutane (Option D) or 2-bromo-3-methylbutane (Option C).
Since the bromination at the tertiary carbon atom is more favourable due to the stability of the resulting intermediate radical, the major product obtained is 2-bromo-2-methylbutane (Option D).
Photo catalysed bromination is a process in which light is used to activate a catalyst to initiate a chemical reaction. In this case, 2-methylbutane is brominated using a photo catalyst.
Reaction mechanism:
The reaction mechanism involves the following steps:
1. Initiation: The photo catalyst absorbs light and becomes excited, leading to the formation of free radicals.
2. Propagation: The free radicals react with the 2-methylbutane to form intermediate radicals.
3. Termination: The intermediate radicals react with each other to form the final product.
The major product obtained in the photo catalysed bromination of 2-methylbutane:
The major product obtained in the photo catalysed bromination of 2-methylbutane is 2-bromo-2-methylbutane (Option D).
Explanation:
When 2-methylbutane is brominated using a photo catalyst, the intermediate radical formed can undergo two different reactions:
1. Bromination at the primary carbon atom: In this case, the intermediate radical reacts with a bromine molecule to form 1-bromo-2-methylbutane (Option A) or 1-bromo-3-methylbutane (Option B).
2. Bromination at the tertiary carbon atom: In this case, the intermediate radical reacts with a bromine molecule to form 2-bromo-2-methylbutane (Option D) or 2-bromo-3-methylbutane (Option C).
Since the bromination at the tertiary carbon atom is more favourable due to the stability of the resulting intermediate radical, the major product obtained is 2-bromo-2-methylbutane (Option D).
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The major product obtained in the photo catalysed bromination of 2-methylbutane is:a)1-bromo-2-methylbutaneb)1-bromo-3-methylbutanec)2-bromo-3-methylbutaned)2-bromo-2-methylbutaneCorrect answer is option 'D'. Can you explain this answer?
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