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The vapour pressure of pure water at 298K is 3.3kpa . Calculate the relative lowering of vapour pressure of an aqueous solution containing 20g of glucose dissolved in 90g of water at the same temperature. (Molar Mass of glucose=180gm/mol , Molar Mass of water =18gm/mol.? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared
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The vapour pressure of pure water at 298K is 3.3kpa . Calculate the relative lowering of vapour pressure of an aqueous solution containing 20g of glucose dissolved in 90g of water at the same temperature. (Molar Mass of glucose=180gm/mol , Molar Mass of water =18gm/mol.?, a detailed solution for The vapour pressure of pure water at 298K is 3.3kpa . Calculate the relative lowering of vapour pressure of an aqueous solution containing 20g of glucose dissolved in 90g of water at the same temperature. (Molar Mass of glucose=180gm/mol , Molar Mass of water =18gm/mol.? has been provided alongside types of The vapour pressure of pure water at 298K is 3.3kpa . Calculate the relative lowering of vapour pressure of an aqueous solution containing 20g of glucose dissolved in 90g of water at the same temperature. (Molar Mass of glucose=180gm/mol , Molar Mass of water =18gm/mol.? theory, EduRev gives you an
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