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The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collision is :
  • a)
  • b)
    0
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The block of massMmoving on the frictionless horizontal surface collid...
According to conservation of energy

MkL2 = p2     (p = mu)
The correct answer is: 
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Community Answer
The block of massMmoving on the frictionless horizontal surface collid...
According to conservation of energy

MkL2 = p2     (p = mu)
The correct answer is: 
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The block of massMmoving on the frictionless horizontal surface collides with the spring of spring constantkand compresses it by lengthL. The maximum momentum of the block after collision is :a)b)0c)d)Correct answer is option 'C'. Can you explain this answer?
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