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If Z is a complex number, then the minimum value of |z| + |z-l| is
  • a)
    1
  • b)
    0
  • c)
    1/2
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If Z is a complex number, then the minimum value of |z| + |z-l| isa)1b...
Note that


, hence minimum value is 1 and it is attained at Z = 0, 1/2
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Most Upvoted Answer
If Z is a complex number, then the minimum value of |z| + |z-l| isa)1b...
Note that


, hence minimum value is 1 and it is attained at Z = 0, 1/2
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Community Answer
If Z is a complex number, then the minimum value of |z| + |z-l| isa)1b...
Explanation:

Definition:
- The modulus of a complex number z = x + yi is defined as |z| = sqrt(x^2 + y^2).
- |z-l| represents the modulus of the difference between z and l, where l is another complex number.

Minimum value of |z| + |z-l|:
- Let z = x + yi, where x and y are real numbers.
- Substituting z into the expression |z| + |z-l| gives us |x + yi| + |x-l + yi|.
- Using the definition of modulus, this expression becomes sqrt(x^2 + y^2) + sqrt((x-l)^2 + y^2).

Minimum value analysis:
- To find the minimum value of the expression sqrt(x^2 + y^2) + sqrt((x-l)^2 + y^2), we can use the triangle inequality.
- The triangle inequality states that for any two complex numbers z1 and z2, |z1 + z2| <= |z1|="" +="">
- Applying the triangle inequality to our expression, we get |z| + |z-l| >= |z - (z-l)| = |l|.
- Therefore, the minimum value of |z| + |z-l| is |l|.

Conclusion:
- In this case, the minimum value of |z| + |z-l| is |l|.
- Hence, the correct answer is option 'A' (1).
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