Given:

2x + 3y - 7 = 0

mean of x = 1

mean deviation of x = 0.3


To find:

Coefficient of mean deviation of y about mean


Solution:

To find the coefficient of mean deviation of y about mean, we first need to calculate the mean and mean deviation of y.

From the given equation:

2x + 3y - 7 = 0

3y = -2x + 7

y = (-2/3)x + 7/3


Now, we know that the mean of x is 1. Therefore, the mean of y can be calculated as:

mean of y = (-2/3) * 1 + 7/3 = 5/3


To calculate the mean deviation of y, we use the formula:

Mean deviation of y = (Σ|yi - mean of y|) / n

where, yi is the ith value of y and n is the total number of values of y.


Let's assume that we have n values of y. Then, we can rewrite the equation of the line as:

y = (-2/3)x/n + 7/3n


Now, we can calculate the values of y for different values of x. Let's assume that we have the following values of y:

y1, y2, y3, ..., yn


Using these values, we can calculate the mean deviation of y as:

Mean deviation of y = (|y1 - mean of y| + |y2 - mean of y| + ... + |yn - mean of y|) / n


Since the mean deviation of x is given as 0.3, we can use the formula:

Mean deviation of x = (Σ|xi - mean of x|) / n

to calculate the values of x for different values of y.


Let's assume that we have the following values of x:

x1, x2, x3, ..., xn


Using these values, we can calculate the mean deviation of x as:

Mean deviation of x = (|x1 - mean of x| + |x2 - mean of x| + ... + |xn - mean of x|) / n


Now, we know that the equation of the line is 2x + 3y - 7 = 0. Therefore, we can write:

x = (7 - 3y) / 2


Using this equation, we can calculate the values of x for different values of y. Let's assume that we have the following values of x:

x1, x2, x3, ..., xn


Using these values, we can calculate the mean deviation of x as:

Mean deviation of x = (|x1 - mean of x| + |x2 - mean of x| + ... + |xn - mean of x|) / n


Now, we can use the formula:

Coefficient of mean deviation of y about mean = (Mean deviation of y / mean of y) / (Mean deviation of