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In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)
Correct answer is between '0.173,0.175'. Can you explain this answer?
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In a cross between two F1 heterozygous tall plants, the F2 progeny con...
This is solved using binomial expansion where p = ¾, q = ¼ , n = 7, x = 4. The answer would be 0.173
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In a cross between two F1 heterozygous tall plants, the F2 progeny con...
Solution:
Given, in a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1.
Let T represent the allele for tallness and t represent the allele for dwarfism.
Thus, the genotype of the F1 heterozygous tall plants can be represented as Tt.
The cross between two F1 heterozygous tall plants can be represented as:
Tt x Tt
| |
Tt Tt
| |
TT Tt
| |
Tt tt
The F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1.
Thus, the probability of getting a tall plant is 3/4 and the probability of getting a dwarf plant is 1/4.
We need to find the probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf.
This can be calculated using the binomial probability formula:
P(X = k) = (n C k)pk(1 - p)n-k
Where,
n = total number of trials = 7
k = number of successes = 4
p = probability of success = 3/4
q = probability of failure = 1/4 = 0.25
P(X = 4) = (7 C 4)(3/4)4(1/4)3
= (35)(27/256)(1/64)
= 0.1748 (approx.)
Therefore, the probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf is 0.1748 (approx.).
Given, in a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1.
Let T represent the allele for tallness and t represent the allele for dwarfism.
Thus, the genotype of the F1 heterozygous tall plants can be represented as Tt.
The cross between two F1 heterozygous tall plants can be represented as:
Tt x Tt
| |
Tt Tt
| |
TT Tt
| |
Tt tt
The F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1.
Thus, the probability of getting a tall plant is 3/4 and the probability of getting a dwarf plant is 1/4.
We need to find the probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf.
This can be calculated using the binomial probability formula:
P(X = k) = (n C k)pk(1 - p)n-k
Where,
n = total number of trials = 7
k = number of successes = 4
p = probability of success = 3/4
q = probability of failure = 1/4 = 0.25
P(X = 4) = (7 C 4)(3/4)4(1/4)3
= (35)(27/256)(1/64)
= 0.1748 (approx.)
Therefore, the probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf is 0.1748 (approx.).
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In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)Correct answer is between '0.173,0.175'. Can you explain this answer?
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In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)Correct answer is between '0.173,0.175'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)Correct answer is between '0.173,0.175'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)Correct answer is between '0.173,0.175'. Can you explain this answer?.
In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)Correct answer is between '0.173,0.175'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)Correct answer is between '0.173,0.175'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a cross between two F1 heterozygous tall plants, the F2 progeny consisted of tall and dwarf plants in the ratio 3 : 1. The probability that out of 7 plants chosen at random, 4 would be tall and 3 would be dwarf ______________ (answer upto 3 decimal points)Correct answer is between '0.173,0.175'. Can you explain this answer?.
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