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If the short wavelength limit of the continuous spectrum coming out of a coolidge tube is 10Å, then the de-Broglie wavelength (in Å)of the electrons reaching the largest metal in the coolidge tube is approximately.
Correct answer is '0.3'. Can you explain this answer?
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If the short wavelength limit of the continuous spectrum coming out of...
The correct answer is: 0.3
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If the short wavelength limit of the continuous spectrum coming out of...
To answer this question, we need some additional information. The short wavelength limit of the continuous spectrum depends on the characteristics of the Coolidge tube, such as the material of the target and the accelerating voltage applied.
Assuming the Coolidge tube is a typical X-ray tube, the short wavelength limit of the continuous spectrum can be calculated using the equation:
λ_min = hc / eV
where λ_min is the minimum wavelength, h is the Planck constant (6.626 x 10^-34 J.s), c is the speed of light (3 x 10^8 m/s), e is the elementary charge (1.602 x 10^-19 C), and V is the accelerating voltage.
Without knowing the specific accelerating voltage applied, we cannot determine the short wavelength limit accurately.
Assuming the Coolidge tube is a typical X-ray tube, the short wavelength limit of the continuous spectrum can be calculated using the equation:
λ_min = hc / eV
where λ_min is the minimum wavelength, h is the Planck constant (6.626 x 10^-34 J.s), c is the speed of light (3 x 10^8 m/s), e is the elementary charge (1.602 x 10^-19 C), and V is the accelerating voltage.
Without knowing the specific accelerating voltage applied, we cannot determine the short wavelength limit accurately.
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The correct answer is: 0.3
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If the short wavelength limit of the continuous spectrum coming out of a coolidge tube is 10Å, then the de-Broglie wavelength (inÅ)of the electrons reaching the largest metal in the coolidge tube is approximately.Correct answer is '0.3'. Can you explain this answer?
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