Answer the following question based on the information given below.The...
Let the Population of Town A in first year be 100.
Thus, population of town A in third year = 105% of 107.50% of 100 = 112.875
But, population of town A in third year = 180600
Population of Town A in first year = (180600 x 100) / 112.875 = 160000
Population of town A in second year = 105% of 160000 = 168000
Hence, Population of town B in second year = 150% of 160000 = 240000
As growth rate of population for town B in the second year was 25%, population of town B in first year = (240000 x 100) /125 = 192000
Also, growth rate becames half in third years of that of in second year.
••• Population of town B in third year = (240000 x 112.5) /100= 270000
For town C, population in second year = Population density x Area = 250 x 1250 = 312500
As growth rate for town C was 11.11% for second year, population of C in first year = (312500 x 100) / 111.11 » 281250
Also, growth rate for town C was 10% for third year, Population of C in third year = 110% of 312500 = 343750
Thus, we can present above data in tabular form as follows:
Required difference = Population of town B in third year - Population of town A in second year
= 270000 - 168000 =102000 Hence, option 3.