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A solution of 80ltrs contains 30% acid. How many litres of pure acid should be added to this solution so that the concentration of acid becomes 65% ?
  • a)
    80
  • b)
    60
  • c)
    85
  • d)
    90
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A solution of 80ltrs contains 30% acid. How many litres of pure acid s...
Let x be the amount of pure acid to be added
0.3(80)+1(x) = 0.65(x+80)
24+x = 0,65x+52
x-0.65x = 52-24
0.35x = 28
x = 80
So the answer is option A.
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Most Upvoted Answer
A solution of 80ltrs contains 30% acid. How many litres of pure acid s...
To solve this problem, we can use the concept of concentration and the formula:

% concentration = (amount of solute / total volume) * 100

Let's break down the problem step by step:

Step 1: Calculate the amount of acid in the original solution.
The original solution contains 80 liters of solution with a concentration of 30% acid. We can calculate the amount of acid in the solution by multiplying the volume of the solution by the concentration of acid:

Amount of acid in the original solution = 80 liters * 30% = 24 liters

Step 2: Calculate the amount of acid needed to reach a 65% concentration.
To find the amount of pure acid needed to reach a 65% concentration, we need to set up an equation:

(amount of acid in original solution + amount of pure acid) / (total volume of solution + amount of pure acid) = 65%

Let's represent the amount of pure acid needed as 'x'.

(24 liters + x) / (80 liters + x) = 65%

Step 3: Solve the equation for 'x'.
To solve the equation, we can cross multiply:

(24 liters + x) * 100 = 65% * (80 liters + x)

2400 + 100x = 5200 + 65x

35x = 2800

x = 2800 / 35

x = 80 liters

So, 80 liters of pure acid should be added to the solution to reach a concentration of 65%.

Therefore, the correct answer is option A) 80 liters.
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A solution of 80ltrs contains 30% acid. How many litres of pure acid should be added to this solution so that the concentration of acid becomes 65% ?a)80b)60c)85d)90Correct answer is option 'A'. Can you explain this answer?
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