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A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass of the block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.
Another block of mass 1.0 kg moving with a speed of 2.0 ms-1 collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________ .
Another block of mass 1.0 kg moving with a speed of 2.0 ms-1 collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________ .
Correct answer is '2.09'. Can you explain this answer?
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A spring-block system is resting on a frictionless floor as shown in t...
Apply conservation of momentum,
Initial momentum = final momentum
1 x u2 = 2v2 + v1
1 x 2 = 2v2 + v1
2v2 + v1 = 2 ...(1)
The coefficient of restitution must be 1, since the collision is perfectly elastic.
v2 - v1 = 2 ....(2)
Solve equation (1) and equation (2),
The time period of the oscillation is,
For a half time period,
The distance of the block after collision is given as,
Initial momentum = final momentum
1 x u2 = 2v2 + v1
1 x 2 = 2v2 + v1
2v2 + v1 = 2 ...(1)
The coefficient of restitution must be 1, since the collision is perfectly elastic.
v2 - v1 = 2 ....(2)
Solve equation (1) and equation (2),
The time period of the oscillation is,
For a half time period,
The distance of the block after collision is given as,
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A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer?
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A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer?.
A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer?.
Solutions for A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is 2.0 Nm-1 and the mass ofthe block is 2.0 kg. Ignore the mass of the spring. Initially the spring is in an unstretched condition.Another block of mass 1.0 kg moving with a speed of 2.0 ms-1collides elastically with the first block. The collision is such that the 2.0 kg block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is ____________.Correct answer is '2.09'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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