6 students of nursery class are playing a game. They are standing in a...
Solution:
To solve this problem, we can use the formula for the number of ways to arrange n objects in a circle, which is (n-1)!.
Step 1:
We need to find the number of ways to arrange 6 objects (the students) in a circle. Using the formula, we get (6-1)! = 5! = 120.
Step 2:
Now that we know there are 120 ways to arrange the students in a circle, we need to count the number of ways they can pass the ball among themselves. Each student can pass the ball to any of the other 5 students, so there are 5 choices for the first pass. After the first pass, there are 5 students left who can receive the ball, so there are 5 choices for the second pass. This continues until all 6 students have passed the ball.
Step 3:
To find the total number of passes, we need to multiply the number of choices for each pass. So the total number of passes is 5 x 5 x 5 x 5 x 5 x 5 = 5^6 = 15625.
Therefore, the correct answer is option B (15625).
6 students of nursery class are playing a game. They are standing in a...
As there are 6 students and each can pass ball to 5 students. so on multiplying 5 six times we get 15625