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If e-x,xe-x are solution of y" + ay' + by = 0, then sum of the values of a and b is _________.
    Correct answer is '3'. Can you explain this answer?
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    If e-x,xe-x are solution of y" + ay + by = 0, then sum of the val...
    Given equation is,y"+ ay' + by = 0 
    and its solution are given by ,e-x and xe-x
     => A.E.i m2 + am + b = 0 has two repeated roots as -1 ,-1
     =>A.E. be (m + 1)2= 0 
    it is only positive when a = 2 and b = 1. 
    => a + b = 2 + 1 = 3
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    If e-x,xe-x are solution of y" + ay + by = 0, then sum of the val...
    To find the solution of y, we need to substitute e^(-x) and xe^(-x) into the differential equation y'' + y = 0.

    Let's start with e^(-x):

    y = e^(-x)
    y' = -e^(-x)
    y'' = e^(-x)

    Substituting these into the differential equation:

    (e^(-x))'' + e^(-x) = 0
    e^(-x) + e^(-x) = 0
    2e^(-x) = 0

    This equation does not hold true for all values of x, so e^(-x) is not a solution of y'' + y = 0.

    Now let's try xe^(-x):

    y = xe^(-x)
    y' = e^(-x) - xe^(-x)
    y'' = -e^(-x) + xe^(-x)

    Substituting these into the differential equation:

    (-e^(-x) + xe^(-x)) + xe^(-x) = 0
    -xe^(-x) + 2xe^(-x) = 0
    xe^(-x) = 0

    This equation holds true for x = 0, so xe^(-x) is a solution of y'' + y = 0.

    Therefore, the solution of y is xe^(-x).
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    If e-x,xe-x are solution of y" + ay + by = 0, then sum of the val...
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    If e-x,xe-x are solution of y" + ay + by = 0, then sum of the values of a and b is _________.Correct answer is '3'. Can you explain this answer?
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