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L and M can do a piece of work in 5 days, while M and N can do the same in 10 days, and N and L can do it in 6 days. Find the number of day(s) it takes to complete the work if all of them work together.
  • a)
    29/7
  • b)
    44
  • c)
    4/2/7
  • d)
    4/7
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
L and M can do a piece of work in 5 days, while M and N can do the sam...
Let total work = LCM of 5, 10 & 6 = 30 units
Efficiency of L and M = 30/5 = 6
Efficiency of M and N = 30/10 = 3
Efficiency of L and M = 30/6= 5
Efficiency of L, M & N = (6 + 5 + 3)/(2) = 7
L, M & N together can complete the work in \frac{30}{7} = 4\frac{2}{7}730​=472​ days
So the answer is option C.
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L and M can do a piece of work in 5 days, while M and N can do the same in 10 days, and N and L can do it in 6 days. Find the number of day(s) it takes to complete the work if all of them work together.a)29/7b)44c)4/2/7d)4/7Correct answer is option 'C'. Can you explain this answer?
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