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A container contains 20 litres of a mixture of methyl, ethyl and propyl alcohol. If 10 litres of a mixture containing methyl and ethyl alcohol in the ratio 2 : 3 is added to the container, the ratio of methyl, ethyl and propyl alcohol become 2 : 3 : 5. If 10 litres of a mixture containing ethyl alcohol and propyl alcohol in the ratio 1 : 3 is added to 20 litres of original solution, what will be the ratio of methyl, ethyl and propyl alcohol in the new solution?
  • a)
    1 : 2 : 9
  • b)
    4 : 11 : 45
  • c)
    3 : 1 2 : 4 5
  • d)
    2 : 3 : 1 0
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A container contains 20 litres of a mixture of methyl, ethyl and propy...
Volume of methyl and ethyl alcohol added to the container are 4 litres and 6 litres respectively.
Volume of methyl alcohol, ethyl alcohol and propyl alcohol in the container are 6 litres, 9 litres and 15 litres respectively.
Volume of methyl alcohol, ethyl alcohol and propyl alcohol in the original solution are 2 litres, 3 litres and 15 litres respectively.
10 litres of a mixture containing ethyl alcohol and propyl alcohol in the ratio 1 : 3 is added to the original solution.
Volume of ethyl alcohol and methyl alcohol added are 2.5 litres and 7.5 litres respectively.
Required Ratio = 2 : ( 3 + 2.5) : (15 + 7.5) = 4 : 11 : 45
Hence, option 2.
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Most Upvoted Answer
A container contains 20 litres of a mixture of methyl, ethyl and propy...
To solve this problem, let's break it down into smaller steps.

Step 1: Initial mixture
The initial mixture contains 20 liters of a mixture of methyl, ethyl, and propyl alcohol. Let's assume the ratio of these alcohols is m:e:p.

Step 2: Adding mixture with methyl and ethyl alcohol
When 10 liters of a mixture containing methyl and ethyl alcohol in the ratio 2:3 is added, the ratio of the alcohols becomes 2:3:5. This gives us the equation:

(m + 2):(e + 3):p = 2:3:5

Step 3: Simplifying the equation
To simplify the equation, let's assume the common ratio as 'k'. This gives us the equation:

(m + 2k):(e + 3k):p = 2k:3k:5k

Step 4: Solving the equation
From the given information, we know that the initial mixture contains 20 liters of alcohol. So, we can write the equation:

m + e + p = 20

Substituting the values from the equation in Step 3, we get:

(m + 2k) + (e + 3k) + p = 20

Simplifying further, we get:

m + e + p + 5k = 20

Since m + e + p = 20, we can rewrite the equation as:

20 + 5k = 20
5k = 0
k = 0

This means that the common ratio, k, is zero. However, this is not possible as k represents the amount of alcohol added to the mixture. Therefore, the given information is inconsistent.

Step 5: Adding mixture with ethyl and propyl alcohol
Since the given information is inconsistent, we cannot determine the ratio of methyl, ethyl, and propyl alcohol in the new solution.
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A container contains 20 litres of a mixture of methyl, ethyl and propyl alcohol. If 10 litres of a mixture containing methyl and ethyl alcohol in the ratio 2 : 3 is added to the container, the ratio of methyl, ethyl and propyl alcohol become 2 : 3 : 5. If 10 litres of a mixture containing ethyl alcohol and propyl alcohol in the ratio 1 : 3 is added to 20 litres of original solution, what will be the ratio of methyl, ethyl and propyl alcohol in the new solution?a)1 : 2 : 9b)4 : 11 : 45c)3 : 1 2 : 4 5d)2 : 3 : 1 0Correct answer is option 'B'. Can you explain this answer?
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