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The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.
Correct answer is '34.98'. Can you explain this answer?
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Verified Answer
The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass ...
34.980094
The 17CI35 atom has 17 protons and 18 neutrons in its nucleus.
M ass o f 1 7 1H1 atom i.e., 17 protons and 17 electrons = 17 * 1.008143
= 17-138431 a.m.u.
Mass of 18 neutrons = 18 * 1.008986
= 18.161748 a.m.u.
Total = 35.300179 a.m.u.
Mass defect Δm = 298/931 = 0.320085 a.m.u.
The atomic mass of 17CI35 would be the sum of the masses of the constituent particles minus the mass equivalent of the binding energy of the nucleus. Hence Atomic mass of 17CI35 = 35.300179 - 0-320085
= 34.980094 a.m.u.
The 17CI35 atom has 17 protons and 18 neutrons in its nucleus.
M ass o f 1 7 1H1 atom i.e., 17 protons and 17 electrons = 17 * 1.008143
= 17-138431 a.m.u.
Mass of 18 neutrons = 18 * 1.008986
= 18.161748 a.m.u.
Total = 35.300179 a.m.u.
Mass defect Δm = 298/931 = 0.320085 a.m.u.
The atomic mass of 17CI35 would be the sum of the masses of the constituent particles minus the mass equivalent of the binding energy of the nucleus. Hence Atomic mass of 17CI35 = 35.300179 - 0-320085
= 34.980094 a.m.u.
Most Upvoted Answer
The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass ...
34.980094
The 17CI35 atom has 17 protons and 18 neutrons in its nucleus.
M ass o f 1 7 1H1 atom i.e., 17 protons and 17 electrons = 17 * 1.008143
= 17-138431 a.m.u.
Mass of 18 neutrons = 18 * 1.008986
= 18.161748 a.m.u.
Total = 35.300179 a.m.u.
Mass defect Δm = 298/931 = 0.320085 a.m.u.
The atomic mass of 17CI35 would be the sum of the masses of the constituent particles minus the mass equivalent of the binding energy of the nucleus. Hence Atomic mass of 17CI35 = 35.300179 - 0-320085
= 34.980094 a.m.u.
The 17CI35 atom has 17 protons and 18 neutrons in its nucleus.
M ass o f 1 7 1H1 atom i.e., 17 protons and 17 electrons = 17 * 1.008143
= 17-138431 a.m.u.
Mass of 18 neutrons = 18 * 1.008986
= 18.161748 a.m.u.
Total = 35.300179 a.m.u.
Mass defect Δm = 298/931 = 0.320085 a.m.u.
The atomic mass of 17CI35 would be the sum of the masses of the constituent particles minus the mass equivalent of the binding energy of the nucleus. Hence Atomic mass of 17CI35 = 35.300179 - 0-320085
= 34.980094 a.m.u.
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The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer?
Question Description
The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer?.
The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer?.
Solutions for The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
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The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer?, a detailed solution for The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? has been provided alongside types of The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The binding energy of 17CI35 nucleus is 298 MeV. Find its atomic mass (in a.m.u.). The mass of hydrogen atom (1H1) is 1 -008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.Correct answer is '34.98'. Can you explain this answer? tests, examples and also practice Physics tests.
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