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If for a silicon npn transistor, the base to emitter voltage (VBE) is 0.7Vand the collector to base voltage (VCB) is 0.2V, then the transistor is operating in the
- a)inverse active mode
- b)cut-off mode
- c)saturation mode
- d)normal active mode
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
If for a silicon npn transistor, the base to emitter voltage (VBE) is ...
VB = 0.7V (Forward-biased)
and VBC = -VCB
= -0.2V (Reverse-biased)
hence, the transistor operates in normal active mode.
The correct answer is: normal active mode
and VBC = -VCB
= -0.2V (Reverse-biased)
hence, the transistor operates in normal active mode.
The correct answer is: normal active mode
Most Upvoted Answer
If for a silicon npn transistor, the base to emitter voltage (VBE) is ...
Operating Modes of a Silicon NPN Transistor
The operating modes of a silicon NPN transistor are determined by the relationship between the voltages applied to its three terminals: the base (B), emitter (E), and collector (C). These modes include the inverse active mode, cut-off mode, saturation mode, and normal active mode.
Base to Emitter Voltage (VBE) and Collector to Base Voltage (VCB)
In the given question, the base to emitter voltage (VBE) is given as 0.7V and the collector to base voltage (VCB) is given as 0.2V. These voltages represent the potential differences between the respective terminals.
Explanation of Transistor Operating Mode
To determine the operating mode of the transistor, we need to analyze the relationship between VBE and VCB.
In an NPN transistor, the base-emitter junction is forward-biased, and the collector-base junction is reverse-biased. This means that the base terminal is at a higher potential than the emitter terminal, while the collector terminal is at a lower potential than the base terminal.
When VBE is greater than zero (forward-biased) and VCB is less than zero (reverse-biased), the transistor operates in the normal active mode. This is the typical mode of operation for amplification purposes.
Comparison with Given Voltages
In the given question, VBE is given as 0.7V, which indicates a forward-biased base-emitter junction. This aligns with the requirements for the normal active mode.
Additionally, VCB is given as 0.2V, which indicates a reverse-biased collector-base junction. This also aligns with the requirements for the normal active mode.
Hence, based on the given voltages, the transistor is operating in the normal active mode.
The operating modes of a silicon NPN transistor are determined by the relationship between the voltages applied to its three terminals: the base (B), emitter (E), and collector (C). These modes include the inverse active mode, cut-off mode, saturation mode, and normal active mode.
Base to Emitter Voltage (VBE) and Collector to Base Voltage (VCB)
In the given question, the base to emitter voltage (VBE) is given as 0.7V and the collector to base voltage (VCB) is given as 0.2V. These voltages represent the potential differences between the respective terminals.
Explanation of Transistor Operating Mode
To determine the operating mode of the transistor, we need to analyze the relationship between VBE and VCB.
In an NPN transistor, the base-emitter junction is forward-biased, and the collector-base junction is reverse-biased. This means that the base terminal is at a higher potential than the emitter terminal, while the collector terminal is at a lower potential than the base terminal.
When VBE is greater than zero (forward-biased) and VCB is less than zero (reverse-biased), the transistor operates in the normal active mode. This is the typical mode of operation for amplification purposes.
Comparison with Given Voltages
In the given question, VBE is given as 0.7V, which indicates a forward-biased base-emitter junction. This aligns with the requirements for the normal active mode.
Additionally, VCB is given as 0.2V, which indicates a reverse-biased collector-base junction. This also aligns with the requirements for the normal active mode.
Hence, based on the given voltages, the transistor is operating in the normal active mode.
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If for a silicon npn transistor, the base to emitter voltage (VBE) is 0.7Vand the collector to base voltage (VCB) is 0.2V, then the transistor is operating in thea)inverse active modeb)cut-off modec)saturation moded)normal active modeCorrect answer is option 'D'. Can you explain this answer?
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