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The product of two numbers is 98838 and the smallest number which is divisible by both of them is 5814. What is the largest number by which both these numbers are divisible?
Correct answer is '17'. Can you explain this answer?
Verified Answer
The product of two numbers is 98838 and the smallest number which is d...
Let the 2 numbers be A and B.
The product of the 2 numbers is 98838, and their L.C.M. is 5814. We need to find their H.C.F.
Now, A x B = H.C.F. x L.C.M., i.e. Product of any two numbers = Product of their H.C.F. and L.C.M.
H.C.F. = 98838/5814
Answer: 17
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Most Upvoted Answer
The product of two numbers is 98838 and the smallest number which is d...
Factors and Divisibility
Factors are numbers that can be multiplied together to get another number. When two numbers have a common factor, it means they can be divided evenly by that number without leaving a remainder. In this case, the product of two numbers is 98838, and the smallest number divisible by both is 5814.

Finding the Common Factors
To find the largest number by which both these numbers are divisible, we need to identify the common factors of 98838 and 5814. The prime factorization of 98838 is 2 x 3 x 16473, while the prime factorization of 5814 is 2 x 3 x 967.

Identifying the Common Factors
By comparing the prime factorizations of both numbers, we can see that the common factors are 2 and 3. To find the largest common factor, we take the smallest power of each common factor that appears in both numbers. In this case, the largest common factor is 2 x 3 = 6.

Final Answer
Therefore, the largest number by which both 98838 and 5814 are divisible is 6. It is important to note that the number 17 mentioned in the question is incorrect based on the provided information and calculations.
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The product of two numbers is 98838 and the smallest number which is divisible by both of them is 5814. What is the largest number by which both these numbers are divisible?Correct answer is '17'. Can you explain this answer?
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