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A rectangle with sides of length (2m – 1) an d (2n – 1) units is divided into squares of unit length by drawing parallel lines as shown in the diagram, then the number of rectangles possible with odd side length s is (2005S)
  • a)
    (m + n – 1)2
  • b)
    4m+n–1
  • c)
    m2n2
  • d)
    m(m + 1)n(n + 1)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A rectangle with sides of length (2m – 1) an d (2n – 1) un...
If we see the blocks in terms of lines then there are 2m vertical lines and 2n horizontal lines. To form the required rectangle we must select two horizontal lines, one even numbered (out of 2, 4, .....2n) and one odd numbered (out of 1, 3....2n–1) and similarly two vertical lines. The number of rectangles is
mC1 .  mC1 . nC1 . nC1 = m2n2
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A rectangle with sides of length (2m – 1) an d (2n – 1) units is divided into squares of unit length by drawing parallel lines as shown in the diagram, then the number of rectangles possible with odd side length s is (2005S)a)(m + n – 1)2b)4m+n–1c)m2n2d)m(m + 1)n(n + 1)Correct answer is option 'C'. Can you explain this answer?
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A rectangle with sides of length (2m – 1) an d (2n – 1) units is divided into squares of unit length by drawing parallel lines as shown in the diagram, then the number of rectangles possible with odd side length s is (2005S)a)(m + n – 1)2b)4m+n–1c)m2n2d)m(m + 1)n(n + 1)Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A rectangle with sides of length (2m – 1) an d (2n – 1) units is divided into squares of unit length by drawing parallel lines as shown in the diagram, then the number of rectangles possible with odd side length s is (2005S)a)(m + n – 1)2b)4m+n–1c)m2n2d)m(m + 1)n(n + 1)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangle with sides of length (2m – 1) an d (2n – 1) units is divided into squares of unit length by drawing parallel lines as shown in the diagram, then the number of rectangles possible with odd side length s is (2005S)a)(m + n – 1)2b)4m+n–1c)m2n2d)m(m + 1)n(n + 1)Correct answer is option 'C'. Can you explain this answer?.
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