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Ten years ago the average age of a family of four members was 28 years. Two children have been born, the present average age of family is same. What are the present ages of the children if the age difference between both the children is 2 years?
  • a)
    7 & 9 years 
  • b)
    6 & 8 years 
  • c)
    7 & 5 years 
  • d)
    Other than given options 
  • e)
    6 & 4 years
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Ten years ago the average age of a family of four members was 28 years...
Ten years ago, total age of four members = 28 × 4 = 112 years
Total age of four members at present = (28 + 10) ×4 = 152 years
And present age of four members + two children = 28 × 6 = 168 years
So age of the two children = 168 – 152 =16
So age of 1st child = 9 years
And age of 2nd child= 7 years
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Ten years ago the average age of a family of four members was 28 years. Two children have been born, the present average age of family is same. What are the present ages of the children if the age difference between both the children is 2 years?a)7 9 yearsb)6 8 yearsc)7 5 yearsd)Other than given optionse)6 4 yearsCorrect answer is option 'A'. Can you explain this answer?
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