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A mass m of water at temperature T1 K is isobarically and adiabatically mixed with an equal mass of water at T2 K. The entropy change of the inverse is
  • a)
  • b)
  • c)
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A mass m of water at temperature T1 K is isobarically and adiabaticall...
A point to note is that, since the process is adiabatic there is no change of the surroundings. We know that for isobaric (constant pressure process), the change in entropy is given by

Now, 
and 
Also, the higher temperature loses heat and the water at the lower temperature gains heat, we can write


⇒ 
Since, 
and 
Total entropy of entropy change of universe




 
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Most Upvoted Answer
A mass m of water at temperature T1 K is isobarically and adiabaticall...
A point to note is that, since the process is adiabatic there is no change of the surroundings. We know that for isobaric (constant pressure process), the change in entropy is given by

Now, 
and 
Also, the higher temperature loses heat and the water at the lower temperature gains heat, we can write


⇒ 
Since, 
and 
Total entropy of entropy change of universe




 
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A mass m of water at temperature T1 K is isobarically and adiabatically mixed with an equal mass of water at T2 K. The entropy change of the inverse isa)b)c)d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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