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If the conjugate depths before and after the jump are 0.5 m and 2.5 m respectively. then loss ofenergy in hydraulic jump will be
- a)0.8 m
- b)1.6 m
- c)3.2 m
- d)6.4 m
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
If the conjugate depths before and after the jump are 0.5 m and 2.5 m ...
Explanation:
Hydraulic jump is a phenomenon that occurs when a high-velocity, low-depth flow transitions to a low-velocity, high-depth flow. When this occurs, there is a significant loss of energy due to turbulence and friction. The loss of energy in a hydraulic jump can be calculated using the following formula:
Loss of energy = (Conjugate depth before jump - Conjugate depth after jump)^2 / (2 x g)
where g is the acceleration due to gravity.
Given that the conjugate depths before and after the jump are 0.5 m and 2.5 m respectively, the loss of energy can be calculated as follows:
Loss of energy = (2.5 - 0.5)^2 / (2 x 9.81)
Loss of energy = 1.6 m
Therefore, the correct answer is option B, 1.6 m.
Summary:
- Hydraulic jump is a phenomenon that occurs when a high-velocity, low-depth flow transitions to a low-velocity, high-depth flow.
- The loss of energy in a hydraulic jump can be calculated using the formula: Loss of energy = (Conjugate depth before jump - Conjugate depth after jump)^2 / (2 x g)
- Given that the conjugate depths before and after the jump are 0.5 m and 2.5 m respectively, the loss of energy is calculated to be 1.6 m.
Hydraulic jump is a phenomenon that occurs when a high-velocity, low-depth flow transitions to a low-velocity, high-depth flow. When this occurs, there is a significant loss of energy due to turbulence and friction. The loss of energy in a hydraulic jump can be calculated using the following formula:
Loss of energy = (Conjugate depth before jump - Conjugate depth after jump)^2 / (2 x g)
where g is the acceleration due to gravity.
Given that the conjugate depths before and after the jump are 0.5 m and 2.5 m respectively, the loss of energy can be calculated as follows:
Loss of energy = (2.5 - 0.5)^2 / (2 x 9.81)
Loss of energy = 1.6 m
Therefore, the correct answer is option B, 1.6 m.
Summary:
- Hydraulic jump is a phenomenon that occurs when a high-velocity, low-depth flow transitions to a low-velocity, high-depth flow.
- The loss of energy in a hydraulic jump can be calculated using the formula: Loss of energy = (Conjugate depth before jump - Conjugate depth after jump)^2 / (2 x g)
- Given that the conjugate depths before and after the jump are 0.5 m and 2.5 m respectively, the loss of energy is calculated to be 1.6 m.
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Community Answer
If the conjugate depths before and after the jump are 0.5 m and 2.5 m ...
Energy loss in hydraulic jump el=( y1-y2)^3/4y1y2
y1 =2.5 y2=0.5
el=1.6
y1 =2.5 y2=0.5
el=1.6
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If the conjugate depths before and after the jump are 0.5 m and 2.5 m respectively. then loss ofenergy in hydraulic jump will bea)0.8 mb)1.6 mc)3.2 md)6.4 mCorrect answer is option 'B'. Can you explain this answer?
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