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Two particles having mass M and m are moving in a circular having radius R and r. If their time periods are same then the radio of angular velocity will be
  • a)
    r/R
  • b)
    R/r
  • c)
    1
  • d)
    √R/r
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two particles having mass M and m are moving in a circular having radi...
We know, T = 2π/w
since, given that T is same for both
therefore, 2π/w1=2π/w2
i.e, w1/w2=1
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Community Answer
Two particles having mass M and m are moving in a circular having radi...
C) 1

The time period of a particle in circular motion is given by T = 2π/ω, where ω is the angular velocity.

Since the time periods of the two particles are the same, we can write:

T1 = T2
2π/ω1 = 2π/ω2

Canceling out the 2π from both sides, we get:

1/ω1 = 1/ω2
ω2 = ω1

The ratio of angular velocities is therefore 1.
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Two particles having mass M and m are moving in a circular having radius R and r. If their time periods are same then the radio of angular velocity will bea)r/Rb)R/rc)1d)√R/rCorrect answer is option 'C'. Can you explain this answer?
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