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If x/4 = y/3 = z/2 then what will be the value of x , y , z if 7x + 8y + 5z = 62
a)(4, 3, 2)
b)(2, 3, 4)
c)(3, 4, 2)
d)(4, 2, 3)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If x/4 = y/3 = z/2 then what will be the value of x , y , z if 7x + 8y...
Let x/4=y/3=z/2=k
x=4k
y=3k
z=2k
7x+8y+5z=62
⇒7*4k+8*3k+5*2k=62
⇒28k+24k+10k=62
⇒62k=62
⇒k=62/62
∴k=1
x=4k
y=3k
z=2k
7x+8y+5z=62
⇒7*4k+8*3k+5*2k=62
⇒28k+24k+10k=62
⇒62k=62
⇒k=62/62
∴k=1
Hence,
x= 4
y=3
z= 2
Most Upvoted Answer
If x/4 = y/3 = z/2 then what will be the value of x , y , z if 7x + 8y...
Given x/4 = y/3 = z/2
Let the common ratio be k
Then x = 4k, y = 3k, z = 2k
Also given, 7x + 8y + 5z = 62
Substituting the values of x, y, z in terms of k, we get:
7(4k) + 8(3k) + 5(2k) = 62
28k + 24k + 10k = 62
62k = 62
k = 1
Therefore, x = 4k = 4(1) = 4
y = 3k = 3(1) = 3
z = 2k = 2(1) = 2
Hence, the values of x, y, z are 4, 3, and 2 respectively.
Therefore, the correct answer is option A: (4, 3, 2).
Let the common ratio be k
Then x = 4k, y = 3k, z = 2k
Also given, 7x + 8y + 5z = 62
Substituting the values of x, y, z in terms of k, we get:
7(4k) + 8(3k) + 5(2k) = 62
28k + 24k + 10k = 62
62k = 62
k = 1
Therefore, x = 4k = 4(1) = 4
y = 3k = 3(1) = 3
z = 2k = 2(1) = 2
Hence, the values of x, y, z are 4, 3, and 2 respectively.
Therefore, the correct answer is option A: (4, 3, 2).
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Community Answer
If x/4 = y/3 = z/2 then what will be the value of x , y , z if 7x + 8y...
In the question it is given that z/3 but where as in answer it looks like z/2 what is this ?????
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