Physics Exam  >  Physics Questions  >  Sodium contains 2.54 x1022free electrons per ... Start Learning for Free
Sodium contains 2.54 x1022   free electrons per cm3 ( given = 6.63 x 10 -34 J-s, m= 9 .11 x 10-31 kg , kB = 1.38 x 10-23 JIK and 1eV = 1.6 x 10-19 J ) , then Fermi D 4 temperature is given in terms of 104 K as?
    Correct answer is '3.6'. Can you explain this answer?
    Most Upvoted Answer
    Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -3...
    We know that 

    ⇒ 

    The correct answer is: 3.6
    Free Test
    Community Answer
    Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -3...
    Given data:
    - Number of free electrons per cm^3 in sodium, n = 2.54 x 10^22 cm^-3
    - Planck's constant, h = 6.63 x 10^-34 J-s
    - Mass of electron, m = 9.11 x 10^-31 kg
    - Boltzmann constant, kB = 1.38 x 10^-23 J/K
    - Conversion factor, 1 eV = 1.6 x 10^-19 J

    Fermi-Dirac Statistics:
    Fermi-Dirac statistics describe the behavior of particles with half-integer spins, such as electrons. According to Fermi-Dirac statistics, the probability of finding a particle with a certain energy is given by the Fermi-Dirac distribution function.

    Fermi Energy:
    The Fermi energy is the maximum energy of an electron at absolute zero temperature. It is denoted by Ef and is given by the formula:

    Ef = (h^2 / 2m) * (3n / 8π)^(2/3)

    where h is Planck's constant, m is the mass of the electron, and n is the number of free electrons per unit volume.

    Converting cm^-3 to m^-3:
    To use the formula for Fermi energy, we need to convert the number of free electrons from cm^-3 to m^-3.

    1 cm^-3 = (1 x 10^-2 m)^-3 = 1 x 10^6 m^-3

    Therefore, the number of free electrons per m^-3 is:

    n = (2.54 x 10^22 cm^-3) x (1 x 10^6 m^-3/cm^-3) = 2.54 x 10^28 m^-3

    Calculating Fermi Energy:
    Using the given values, we can calculate the Fermi energy as follows:

    Ef = (h^2 / 2m) * (3n / 8π)^(2/3)
    = ((6.63 x 10^-34 J-s)^2 / (2 x 9.11 x 10^-31 kg)) * (3(2.54 x 10^28 m^-3) / (8π))^(2/3)
    = (4.83 x 10^-68 J^2-s^2 / kg) * (1.91 x 10^28 m^-3)^(2/3)

    Simplifying the calculation:

    Ef = 7.18 x 10^-68 J^2-s^2 / kg * (1.91 x 10^28)^(2/3) m^-2

    Converting Fermi Energy to eV:
    Since the given answer is in terms of 10^4 K, we need to convert the Fermi energy from joules to electron volts.

    1 eV = 1.6 x 10^-19 J

    Therefore, the Fermi energy in eV is:

    Ef (eV) = Ef / (1.6 x 10^-19 J/eV)

    Calculating the Fermi Temperature:
    The Fermi temperature (TF) is defined as the temperature at which the thermal energy (
    Explore Courses for Physics exam

    Similar Physics Doubts

    Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer?
    Question Description
    Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer?.
    Solutions for Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics. Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free.
    Here you can find the meaning of Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer?, a detailed solution for Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer? has been provided alongside types of Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Sodium contains 2.54 x1022free electrons per cm3( given = 6.63 x 10 -34J-s, m=9 .11 x 10-31kg , kB= 1.38 x 10-23JIK and 1eV = 1.6 x 10-19J ) , then Fermi D 4 temperature is given in terms of 104 K as?Correct answer is '3.6'. Can you explain this answer? tests, examples and also practice Physics tests.
    Explore Courses for Physics exam
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev