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A beam of protons enters a uniform magnetic field of 0.3T  with velocity of 4 × 105 m/s  in a direction making an angle of 60° with the direction of magnetic field, the pitch of the helix (in metres) will be :
    Correct answer is '0.0437'. Can you explain this answer?
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    A beam of protons enters a uniform magnetic field of0.3T with velocity...
    The correct answer is: 0.0437
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    A beam of protons enters a uniform magnetic field of0.3T with velocity...
    In order to determine the effect of the magnetic field on the protons, we need to use the formula for the magnetic force on a charged particle:

    F = qvB sinθ

    Where:
    F = magnetic force on the proton (in Newtons)
    q = charge of the proton (in Coulombs)
    v = velocity of the proton (in meters per second)
    B = magnetic field strength (in Tesla)
    θ = angle between the velocity vector and the magnetic field vector (in degrees)

    Since the protons have a positive charge and are moving perpendicular to the magnetic field, the angle θ is 90 degrees. Therefore, sinθ = 1.

    Assuming the charge of the proton is 1.6 x 10^-19 Coulombs, and the velocity is 4 x 10^6 meters per second, we can calculate the magnetic force:

    F = (1.6 x 10^-19 C)(4 x 10^6 m/s)(0.3 T)(1)

    F = 1.92 x 10^-13 N

    So, the magnetic force on the protons is 1.92 x 10^-13 Newtons.
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    A beam of protons enters a uniform magnetic field of0.3T with velocity...
    The correct answer is: 0.0437
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    A beam of protons enters a uniform magnetic field of0.3T with velocity of4 × 105m/sin a direction making an angle of 60° with the direction of magnetic field, the pitch of the helix (inmetres) will be :Correct answer is '0.0437'. Can you explain this answer?
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