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A carnot engine accepts 1000 calorie heat at 500K and give back 400 calorie heat to sink. What temperature is of sink?
  • a)
    200 K
  • b)
    300 K
  • c)
    150 K
  • d)
    400 K
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A carnot engine accepts 1000 calorie heat at 500K and give back 400 ca...
Q1 =1000 calories
Q2 =400 calories
T= 500 k
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Most Upvoted Answer
A carnot engine accepts 1000 calorie heat at 500K and give back 400 ca...
Q1 =1000 calories
Q2 =400 calories
T= 500 k
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Community Answer
A carnot engine accepts 1000 calorie heat at 500K and give back 400 ca...
Heat taken =1000 cal
Heat rejected = 400 cal
So, work done = 600 cal
Efficiency = eta = work done / total heat given = 1 - t (cold)/t (hot)
This implies, 600/1000 = 1 - t (cold)/500
On solving we get option A
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A carnot engine accepts 1000 calorie heat at 500K and give back 400 calorie heat to sink. What temperature is of sink?a)200 Kb)300 Kc)150 Kd)400 KCorrect answer is option 'A'. Can you explain this answer?
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