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In the figure shown A  B  C  D  E  F  A  was a square loop of side l, but is folded in two equal parts so that half of it lies in x z plane and the other half lies in the  i'. The magnetic field at the centre is :
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In the figure shownA B C D E F A was a square loop of sidel,but is fol...
Due to FABC  the magnetic field at O  is along y-axis and due to CDEF  the magnetic field is along x-axis.
Hence the field will be of the form 
Calculating field due to FABC :
due to AB :
Due to BC :
Similarly due to FA :
Similarly due to CDEF :
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Most Upvoted Answer
In the figure shownA B C D E F A was a square loop of sidel,but is fol...
Due to FABC  the magnetic field at O  is along y-axis and due to CDEF  the magnetic field is along x-axis.
Hence the field will be of the form 
Calculating field due to FABC :
due to AB :
Due to BC :
Similarly due to FA :
Similarly due to CDEF :
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In the figure shownA B C D E F A was a square loop of sidel,but is folded in two equal parts so that half of it lies inx zplane and the other half lies in thei. The magnetic field at the centre is :a)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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