Solution:

To determine how many litres of n/10 solution can be prepared from 63g of oxalic acid, we need to use the formula:

n = m/MV

Where:

n = number of moles of solute

m = mass of solute (in grams)

M = molar mass of solute (in grams/mole)

V = volume of solution (in liters)

First, we need to calculate the number of moles of oxalic acid present in 63g.

The molar mass of oxalic acid is 90.04 g/mol.

Therefore, the number of moles of oxalic acid present in 63g is:

n = m/M = 63/90.04 = 0.699 moles

Next, we need to calculate the volume of n/10 solution that can be prepared using this amount of oxalic acid.

We know that the concentration of n/10 solution is 1/10 of the normal concentration, which is 1 mole/liter. Therefore, the concentration of n/10 solution is:

C = 1/10 x 1 = 0.1 moles/liter

Using the formula above, we can rearrange it to solve for V:

V = m/Mn/C

Substituting the values we have:

V = 63/90.04/0.1 = 6.997 liters

Therefore, we can prepare 6.997 liters of n/10 solution from 63g of oxalic acid.

However, since we cannot measure a fractional amount of solution, we need to round up this value to the nearest whole number.

Thus, the correct answer is 10 liters of n/10 solution that can be prepared from 63g of oxalic acid.