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There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratio
- a)251 : 163
- b)239 : 161
- c)220 : 149
- d)229 : 141
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
There are two drums, each containing a mixture of paints A and B. In d...
It is given that in drum 1, A and B are in the ratio 18 : 7.
Let us assume that in drum 2, A and B are in the ratio x : 1.
It is given that drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7.
Therefore, we can say that in drum 2, A and B are in the ratio
Let us assume that in drum 2, A and B are in the ratio x : 1.
It is given that drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7.
Therefore, we can say that in drum 2, A and B are in the ratio
Most Upvoted Answer
There are two drums, each containing a mixture of paints A and B. In d...
Given:
Ratio of A and B in drum 1 = 18 : 7
Ratio of A and B in final mixture = 13 : 7
Mixing ratio of drum 1 and drum 2 = 3 : 4
To Find: Ratio of A and B in drum 2
Solution:
Let the quantity of mixture in drum 1 be 3x and in drum 2 be 4x.
Then, in drum 1:
Quantity of A = 18/25 * 3x = 54x/25
Quantity of B = 7/25 * 3x = 21x/25
In drum 2:
Quantity of A = a * 4x
Quantity of B = b * 4x
where a and b are some constants.
In the final mixture:
Quantity of A = 13/20 * (3x + 4x) = 39x/20 + 13x/5 = 104x/20
Quantity of B = 7/20 * (3x + 4x) = 21x/20 + 28x/20 = 49x/20
Since the final mixture is obtained by mixing the mixtures from drum 1 and drum 2 in the ratio 3 : 4, we can write:
Quantity of A in final mixture = (3/7) * Quantity of A in drum 1 + (4/7) * Quantity of A in drum 2
Quantity of B in final mixture = (3/7) * Quantity of B in drum 1 + (4/7) * Quantity of B in drum 2
Substituting the values, we get:
104x/20 = (3/7) * 54x/25 + (4/7) * a * 4x
49x/20 = (3/7) * 21x/25 + (4/7) * b * 4x
Simplifying the equations, we get:
a = 239/161
b = 161/239
Therefore, the ratio of A and B in drum 2 = a : b = 239 : 161
Hence, option B is the correct answer.
Ratio of A and B in drum 1 = 18 : 7
Ratio of A and B in final mixture = 13 : 7
Mixing ratio of drum 1 and drum 2 = 3 : 4
To Find: Ratio of A and B in drum 2
Solution:
Let the quantity of mixture in drum 1 be 3x and in drum 2 be 4x.
Then, in drum 1:
Quantity of A = 18/25 * 3x = 54x/25
Quantity of B = 7/25 * 3x = 21x/25
In drum 2:
Quantity of A = a * 4x
Quantity of B = b * 4x
where a and b are some constants.
In the final mixture:
Quantity of A = 13/20 * (3x + 4x) = 39x/20 + 13x/5 = 104x/20
Quantity of B = 7/20 * (3x + 4x) = 21x/20 + 28x/20 = 49x/20
Since the final mixture is obtained by mixing the mixtures from drum 1 and drum 2 in the ratio 3 : 4, we can write:
Quantity of A in final mixture = (3/7) * Quantity of A in drum 1 + (4/7) * Quantity of A in drum 2
Quantity of B in final mixture = (3/7) * Quantity of B in drum 1 + (4/7) * Quantity of B in drum 2
Substituting the values, we get:
104x/20 = (3/7) * 54x/25 + (4/7) * a * 4x
49x/20 = (3/7) * 21x/25 + (4/7) * b * 4x
Simplifying the equations, we get:
a = 239/161
b = 161/239
Therefore, the ratio of A and B in drum 2 = a : b = 239 : 161
Hence, option B is the correct answer.
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There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer?
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There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer?.
There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer?.
Solutions for There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT.
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There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer?, a detailed solution for There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratioa)251 : 163b)239 : 161c)220 : 149d)229 : 141Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice CAT tests.
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