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There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratio
- a)251:163
- b)239:161
- c)220:149
- d)229:141
Correct answer is option 'B'. Can you explain this answer?
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There are two drums, each containing a mixture of paints A and B. In ...
It is given that in drum 1, A and B are in the ratio 18:7.
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Let us assume that in drum 2, A and B are in the ratio x: 1.
It is given that drums 1 and 2 are mixed in the ratio 3:4 and in this final mixture, A and B are in the ratio 13:7.
By equating concentration of A
3 * 18/ (18 + 7 + 4) * x/(x + 1)
=>3 + 4=13/ (13 + 7)
=>54/25 + 4x/x+1 = 91/20
=> 4x/(x+1)= 239/100
=>x= 239/161
Therefore, we can say that in drum, 2, A and B are in the ratio 239/161 :1 or 239:161.
Most Upvoted Answer
There are two drums, each containing a mixture of paints A and B. In ...
Solution:
Given: The ratio of A and B in drum 1 = 18:7
Let the quantity of mixture in drum 1 = 18x+7x = 25x (assume the common ratio as x)
Let the quantity of mixture in drum 2 = y (assume the quantity of mixture in drum 2 as y)
Let the quantity of mixture taken from drum 1 and drum 2 = 3u and 4u respectively.
Ratio of mixture taken from drum 1 and drum 2 = 3:4
The final mixture has the ratio of A and B as 13:7
Therefore, the mixture taken from drum 1 has the ratio of A and B as (18/25)x and (7/25)x respectively.
Similarly, the mixture taken from drum 2 has the ratio of A and B as (a/251)y and (b/251)y respectively.
Now, the final mixture has the ratio of A and B as 13:7.
Therefore, the ratio of mixture taken from drum 1 and drum 2 is given as:
(18/25)x*(3u) + (a/251)y*(4u) : (7/25)x*(3u) + (b/251)y*(4u) = 13:7
Simplifying the above equation, we get:
54ax + 12uy = 39bx + 28uy
54ax - 39bx = 16uy
3x(18a - 13b) = 16u*y
We know that the quantity of mixture taken from drum 1 and drum 2 is in the ratio 3:4.
Therefore, 3u/4u = (25x)/(251y)
12x = 25y
x/y = 25/12
Substituting the value of x/y in the equation 3x(18a - 13b) = 16u*y, we get:
3*25/12*(18a - 13b) = 16u
25(54a - 39b) = 64u
54a - 39b = 64u/25
Therefore, the ratio of A and B in drum 2 is given by:
a/b = (13/7)/(18/7) * (251/64) = 239/161
Hence, the correct option is (B) 239:161.
Given: The ratio of A and B in drum 1 = 18:7
Let the quantity of mixture in drum 1 = 18x+7x = 25x (assume the common ratio as x)
Let the quantity of mixture in drum 2 = y (assume the quantity of mixture in drum 2 as y)
Let the quantity of mixture taken from drum 1 and drum 2 = 3u and 4u respectively.
Ratio of mixture taken from drum 1 and drum 2 = 3:4
The final mixture has the ratio of A and B as 13:7
Therefore, the mixture taken from drum 1 has the ratio of A and B as (18/25)x and (7/25)x respectively.
Similarly, the mixture taken from drum 2 has the ratio of A and B as (a/251)y and (b/251)y respectively.
Now, the final mixture has the ratio of A and B as 13:7.
Therefore, the ratio of mixture taken from drum 1 and drum 2 is given as:
(18/25)x*(3u) + (a/251)y*(4u) : (7/25)x*(3u) + (b/251)y*(4u) = 13:7
Simplifying the above equation, we get:
54ax + 12uy = 39bx + 28uy
54ax - 39bx = 16uy
3x(18a - 13b) = 16u*y
We know that the quantity of mixture taken from drum 1 and drum 2 is in the ratio 3:4.
Therefore, 3u/4u = (25x)/(251y)
12x = 25y
x/y = 25/12
Substituting the value of x/y in the equation 3x(18a - 13b) = 16u*y, we get:
3*25/12*(18a - 13b) = 16u
25(54a - 39b) = 64u
54a - 39b = 64u/25
Therefore, the ratio of A and B in drum 2 is given by:
a/b = (13/7)/(18/7) * (251/64) = 239/161
Hence, the correct option is (B) 239:161.
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There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer?
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There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer?.
There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer?.
Solutions for There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18:7. The mixtures from drums 1 and 2 are mixed in the ratio 3: 4 and in this final mixture, A and B are in the ratio 13:7. In drum 2, then A and B were in the ratioa) 251:163b) 239:161c) 220:149d) 229:141Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT.
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