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A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field in a direction perpendicular to that of fixed diameter
- a)The emf will be maximum at the moment when flux is zero
- b)The emf will be zero at the moment when flux is maximum
- c)The emf will be maximum at the moment when plane of the loop is parallel to the magnetic field .
- d)The phase difference between the flux & the emf is π/2
Correct answer is option 'A,B,C,D'. Can you explain this answer?
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A conducting loop rotates with constant angular velocity about its fix...
All are correct options.
i.e the emf induced is equal to change in magnetic flux per unit time.
i.e the emf induced is equal to change in magnetic flux per unit time.Most Upvoted Answer
A conducting loop rotates with constant angular velocity about its fix...
The correct option is c) The emf will be maximum at the moment when the plane of the loop is parallel to the magnetic field.
According to Faraday's law of electromagnetic induction, the induced emf in a conducting loop is given by the rate of change of magnetic flux through the loop. The magnetic flux is given by the product of the magnetic field strength and the area of the loop.
When the plane of the loop is parallel to the magnetic field, the magnetic flux through the loop is maximum because the area of the loop is maximum. Therefore, the rate of change of magnetic flux will be maximum at this moment, leading to the maximum induced emf.
When the flux is zero, it means that the loop is perpendicular to the magnetic field, and the area of the loop that is in the magnetic field is zero. Therefore, the induced emf will be zero at this moment.
So, option a) is incorrect.
Similarly, when the flux is maximum, it means that the loop is parallel to the magnetic field, and the area of the loop that is in the magnetic field is maximum. Therefore, the induced emf will be maximum at this moment.
So, option b) is incorrect.
The phase difference between the flux and the induced emf will depend on the specific situation and the relative orientations of the loop and the magnetic field. It is not possible to determine the phase difference based on the given information.
Therefore, the correct option is c) The emf will be maximum at the moment when the plane of the loop is parallel to the magnetic field.
According to Faraday's law of electromagnetic induction, the induced emf in a conducting loop is given by the rate of change of magnetic flux through the loop. The magnetic flux is given by the product of the magnetic field strength and the area of the loop.
When the plane of the loop is parallel to the magnetic field, the magnetic flux through the loop is maximum because the area of the loop is maximum. Therefore, the rate of change of magnetic flux will be maximum at this moment, leading to the maximum induced emf.
When the flux is zero, it means that the loop is perpendicular to the magnetic field, and the area of the loop that is in the magnetic field is zero. Therefore, the induced emf will be zero at this moment.
So, option a) is incorrect.
Similarly, when the flux is maximum, it means that the loop is parallel to the magnetic field, and the area of the loop that is in the magnetic field is maximum. Therefore, the induced emf will be maximum at this moment.
So, option b) is incorrect.
The phase difference between the flux and the induced emf will depend on the specific situation and the relative orientations of the loop and the magnetic field. It is not possible to determine the phase difference based on the given information.
Therefore, the correct option is c) The emf will be maximum at the moment when the plane of the loop is parallel to the magnetic field.
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A conducting loop rotates with constant angular velocity about its fix...
All are correct options.
i.e the emf induced is equal to change in magnetic flux per unit time.
i.e the emf induced is equal to change in magnetic flux per unit time.
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A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field in a direction perpendicular to that of fixed diametera)The emf will be maximum at the moment when flux is zerob)The emf will be zero at the moment when flux is maximumc)The emf will be maximum at the moment when plane of the loop is parallelto the magnetic field .d)The phase difference between the flux & the emf isπ/2Correct answer is option 'A,B,C,D'. Can you explain this answer?
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A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field in a direction perpendicular to that of fixed diametera)The emf will be maximum at the moment when flux is zerob)The emf will be zero at the moment when flux is maximumc)The emf will be maximum at the moment when plane of the loop is parallelto the magnetic field .d)The phase difference between the flux & the emf isπ/2Correct answer is option 'A,B,C,D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field in a direction perpendicular to that of fixed diametera)The emf will be maximum at the moment when flux is zerob)The emf will be zero at the moment when flux is maximumc)The emf will be maximum at the moment when plane of the loop is parallelto the magnetic field .d)The phase difference between the flux & the emf isπ/2Correct answer is option 'A,B,C,D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field in a direction perpendicular to that of fixed diametera)The emf will be maximum at the moment when flux is zerob)The emf will be zero at the moment when flux is maximumc)The emf will be maximum at the moment when plane of the loop is parallelto the magnetic field .d)The phase difference between the flux & the emf isπ/2Correct answer is option 'A,B,C,D'. Can you explain this answer?.
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Solutions for A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field in a direction perpendicular to that of fixed diametera)The emf will be maximum at the moment when flux is zerob)The emf will be zero at the moment when flux is maximumc)The emf will be maximum at the moment when plane of the loop is parallelto the magnetic field .d)The phase difference between the flux & the emf isπ/2Correct answer is option 'A,B,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
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ample number of questions to practice A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field in a direction perpendicular to that of fixed diametera)The emf will be maximum at the moment when flux is zerob)The emf will be zero at the moment when flux is maximumc)The emf will be maximum at the moment when plane of the loop is parallelto the magnetic field .d)The phase difference between the flux & the emf isπ/2Correct answer is option 'A,B,C,D'. Can you explain this answer? tests, examples and also practice Physics tests.
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