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Two circular rings of identical radii and resistance of 36Ω each are placed in such a way that they cross each other’s centre C1 and C2 as shown in figure. Conducting joints are made at intersection points  and  of the rings. An ideal cell of emf 20 volts is connected across AB. The power delivered (in watt) by cell is :
    Correct answer is '100'. Can you explain this answer?
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    Two circular rings of identical radii and resistance of 36Ω each...
    From the figure.
    AC1 = AC2 = C1C2 = radius
    Hence the resistance of four section are
    Hence equivalent resistance R  across AB  is
    The correct answer is: 100
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    Most Upvoted Answer
    Two circular rings of identical radii and resistance of 36Ω each...
    First we have to calculate the resistance per unit length.
    if the radius of each circle is R
    then ρ=36/(2πR) i.e resistance per unit length and
    the one intersection point and the two center of the circle forms a equilateral triangle, and for total they forms two such triangles up side down..
    then the length intersected by each circle is =Rθ , and here θ is 2π/3...so we get 2πR/3 and now resistance of that cutted length is (36/(2πR)) * ((2πR/3))=12 ohm and the rest is (36-12)=24 ohm..

    now see the picture carefully....there are four resistances i.e. 24,12,12,24 ohms are in parallel connection...
    calculating this we can get equivalent resistance
    4 ohms
    and we know the formula of the power of a cell i.e.

    ξ²/R ...where ξ is the emf of the cell and we now get the power 20²/4= 400/4=100 watt...

    I think it will be helpful for you.
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    Community Answer
    Two circular rings of identical radii and resistance of 36Ω each...
    From the figure.
    AC1 = AC2 = C1C2 = radius
    Hence the resistance of four section are
    Hence equivalent resistance R  across AB  is
    The correct answer is: 100
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    Two circular rings of identical radii and resistance of 36Ω each are placed in such a way that they cross each other’s centreC1andC2as shown in figure. Conducting joints are made at intersection pointsAandBof the rings. An ideal cell of emf 20voltsis connected acrossAB. The power delivered (inwatt) by cell is :Correct answer is '100'. Can you explain this answer?
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    Two circular rings of identical radii and resistance of 36Ω each are placed in such a way that they cross each other’s centreC1andC2as shown in figure. Conducting joints are made at intersection pointsAandBof the rings. An ideal cell of emf 20voltsis connected acrossAB. The power delivered (inwatt) by cell is :Correct answer is '100'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Two circular rings of identical radii and resistance of 36Ω each are placed in such a way that they cross each other’s centreC1andC2as shown in figure. Conducting joints are made at intersection pointsAandBof the rings. An ideal cell of emf 20voltsis connected acrossAB. The power delivered (inwatt) by cell is :Correct answer is '100'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two circular rings of identical radii and resistance of 36Ω each are placed in such a way that they cross each other’s centreC1andC2as shown in figure. Conducting joints are made at intersection pointsAandBof the rings. An ideal cell of emf 20voltsis connected acrossAB. The power delivered (inwatt) by cell is :Correct answer is '100'. Can you explain this answer?.
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