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The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B.
Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is
  • a)
    6
  • b)
    4
  • c)
    3
  • d)
    5
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The distance from A to B is 60 km. Partha and Narayan start from A at ...
Let the time taken by Partha to cover 60 km be x hours.
Narayan will cover 60 km in x-4 hours.

Partha reaches the mid-point of A and B two hours before Narayan reaches B.

Partha will take 12 hours to cross 60 km.

Therefore, option D is the right answer.
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Most Upvoted Answer
The distance from A to B is 60 km. Partha and Narayan start from A at ...
Given: Distance from A to B = 60 km

Let the speed of Narayan be x km/hr.
Therefore, the speed of Partha will be (x/2) km/hr (since Partha reaches the midpoint of A and B two hours before Narayan reaches B).

Let the time taken by Narayan to reach B be t hours.
Therefore, the time taken by Partha to reach B will be (t + 4) hours.

Using the formula: distance = speed × time,
We can form two equations as follows:

For Narayan:
60 = x × t

For Partha:
30 = (x/2) × (t+2) (since the midpoint of A and B is 30 km from A)
60 = (x/2) × (t+4)

Solving the above equations, we get:
x = 10 km/hr (speed of Narayan)
Therefore, speed of Partha = (x/2) = 5 km/hr (option D)

Hence, the correct answer is option D.
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Community Answer
The distance from A to B is 60 km. Partha and Narayan start from A at ...
Let the time taken by Narayan be x
then time taken by Parth is x+4
x+4/2=x-2
x+4=2x-4
x=8
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