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The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is
- a)6
- b)4
- c)3
- d)5
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The distance from A to B is 60 km. Partha and Narayan start from A at ...
Let the time taken by Partha to cover 60 km be x hours.
Narayan will cover 60 km in x-4 hours.
Speed of Partha = 60/x
Speed of Narayan = 60/(x-4)
Partha reaches the mid-point of A and B two hours before Narayan reaches B.
⇒
⇒ x/2 + 2 = x – 4
⇒ x+4/2 = x-4
x + 4 = 2x − 8 x = 12
Partha will take 12 hours to cross 60 km.
⇒ Speed of Partha = 60/12 = 5 Kmph.
Therefore, option D is the right answer.
Most Upvoted Answer
The distance from A to B is 60 km. Partha and Narayan start from A at ...
Given Information:
- Distance from A to B = 60 km
- Partha takes 4 hours more than Narayan to reach B
- Partha reaches the mid-point of A and B 2 hours before Narayan reaches B
Let's Assume:
- Let the speed of Narayan be x km/hr
- Let the speed of Partha be y km/hr
Calculations:
- Time taken by Narayan to reach B = 60/x hours
- Time taken by Partha to reach B = 60/y hours
- Given, Partha takes 4 hours more than Narayan to reach B: 60/y = 60/x + 4
- Given, Partha reaches the mid-point of A and B 2 hours before Narayan reaches B: 30/y = 60/x - 2
Solving the equations:
- From the first equation, we get y = x - 15
- Substituting y = x - 15 in the second equation, we get 30/(x-15) = 60/x - 2
- Solving this equation, we get x = 10
Calculating Partha's speed:
- Substituting x = 10 in y = x - 15, we get y = 10 - 15 = 5 km/hr
Therefore, the speed of Partha is 5 km/hr, which corresponds to option 'D'.
- Distance from A to B = 60 km
- Partha takes 4 hours more than Narayan to reach B
- Partha reaches the mid-point of A and B 2 hours before Narayan reaches B
Let's Assume:
- Let the speed of Narayan be x km/hr
- Let the speed of Partha be y km/hr
Calculations:
- Time taken by Narayan to reach B = 60/x hours
- Time taken by Partha to reach B = 60/y hours
- Given, Partha takes 4 hours more than Narayan to reach B: 60/y = 60/x + 4
- Given, Partha reaches the mid-point of A and B 2 hours before Narayan reaches B: 30/y = 60/x - 2
Solving the equations:
- From the first equation, we get y = x - 15
- Substituting y = x - 15 in the second equation, we get 30/(x-15) = 60/x - 2
- Solving this equation, we get x = 10
Calculating Partha's speed:
- Substituting x = 10 in y = x - 15, we get y = 10 - 15 = 5 km/hr
Therefore, the speed of Partha is 5 km/hr, which corresponds to option 'D'.
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The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, isa)6b)4c)3d)5Correct answer is option 'D'. Can you explain this answer?
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