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The 6th term of a G.P. is 32 and its 8th term is 128 ; then the common ratio of the G.P. is
  • a)
    -1
  • b)
    2
  • c)
    4
  • d)
    -4
Correct answer is option 'B'. Can you explain this answer?
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The 6th term of a G.P. is 32 and its 8th term is 128 ; then the common...
The nth tan of a G.P is (tn) = arn - 1
t6 = a.r5 = 32
t8 = a.r7 = 128
r 5 r 7 = 32 128
or 1 r 2 = 1 4
or r2 = (2)2
or r = 2
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The 6th term of a G.P. is 32 and its 8th term is 128 ; then the common...
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The 6th term of a G.P. is 32 and its 8th term is 128 ; then the common...
The formula to find the nth term of a geometric progression (G.P.) is given by:

an = a * r^(n-1)

Where:
an = nth term of the G.P.
a = first term of the G.P.
r = common ratio of the G.P.
n = term number

Given that the 6th term (a6) is 32, we can substitute the values into the formula:

32 = a * r^(6-1)
32 = a * r^5

Similarly, the 8th term (a8) is given as 128:

128 = a * r^(8-1)
128 = a * r^7

To find the common ratio (r), we can divide the equation for the 8th term by the equation for the 6th term:

(128 / 32) = (a * r^7) / (a * r^5)
4 = r^2
√4 = r
r = 2 or -2

Both 2 and -2 are valid solutions for the common ratio. However, we can determine which one is correct by substituting the values back into the equations.

For r = 2:
32 = a * 2^5
32 = a * 32
a = 1

For r = -2:
32 = a * (-2)^5
32 = a * (-32)
a = -1

Since the first term (a) is not specified in the question, it can have multiple values. However, the common ratio (r) can only be either 2 or -2.

Therefore, the correct answer is option 'B', r = 2.
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The 6th term of a G.P. is 32 and its 8th term is 128 ; then the common ratio of the G.P. isa) -1 b) 2 c) 4 d) -4 Correct answer is option 'B'. Can you explain this answer?
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