A body with initial velocity of 18 km acceleration uniformly at the ra...
Calculation of Final Velocity of a Body with Uniformly Accelerating MotionGiven:
Initial velocity (u) = 18 km/hr = 5 m/s
Acceleration (a) = 9 cm/s²
Distance (s) = 200 m
Calculating Final Velocity:
We know that,
v² = u² + 2as
where,
v = final velocity
u = initial velocity
a = acceleration
s = distance
Converting initial velocity into SI unit:
u = 18 km/hr = 18 × 1000 m/3600 s = 5 m/s
Putting the given values in the formula:
v² = (5)² + 2(0.09)(200)
v² = 25 + 36
v² = 61
v = √61 m/s
Therefore, the final velocity of the body is √61 m/s.
Explanation:
When a body is moving with a uniform acceleration, its final velocity can be calculated using the formula v² = u² + 2as. In this formula, v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance travelled by the body.
In the given problem, the initial velocity of the body is 18 km/hr, which is converted into SI unit of m/s. The acceleration of the body is given as 9 cm/s² and the distance travelled by the body is 200 m.
By putting these values in the formula v² = u² + 2as, we can calculate the final velocity of the body. After simplification, we get the final velocity of the body as √61 m/s.
Therefore, the final velocity of the body is √61 m/s.