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A body with initial velocity of 18 km acceleration uniformly at the rate of 9 cm/s over a distance of 200 m. calculate the final velocity in S.I units?
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A body with initial velocity of 18 km acceleration uniformly at the ra...
Calculation of Final Velocity of a Body with Uniformly Accelerating Motion

Given:

Initial velocity (u) = 18 km/hr = 5 m/s

Acceleration (a) = 9 cm/s²

Distance (s) = 200 m

Calculating Final Velocity:


We know that,

v² = u² + 2as

where,

v = final velocity

u = initial velocity

a = acceleration

s = distance

Converting initial velocity into SI unit:

u = 18 km/hr = 18 × 1000 m/3600 s = 5 m/s

Putting the given values in the formula:

v² = (5)² + 2(0.09)(200)

v² = 25 + 36

v² = 61

v = √61 m/s

Therefore, the final velocity of the body is √61 m/s.

Explanation:


When a body is moving with a uniform acceleration, its final velocity can be calculated using the formula v² = u² + 2as. In this formula, v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance travelled by the body.

In the given problem, the initial velocity of the body is 18 km/hr, which is converted into SI unit of m/s. The acceleration of the body is given as 9 cm/s² and the distance travelled by the body is 200 m.

By putting these values in the formula v² = u² + 2as, we can calculate the final velocity of the body. After simplification, we get the final velocity of the body as √61 m/s.

Therefore, the final velocity of the body is √61 m/s.
Community Answer
A body with initial velocity of 18 km acceleration uniformly at the ra...
Given,
u = 18km/h = 18*1000/3600 m/s = 5m/s
a = 9cm/s² = 9*0.01 m/s² = 0.09m/s²
s = 200m
v = ?
v² = u²+2as
v² = 5²+2(0.09)(200)
v² = 25+36
v² = 61
v = √61
v =7.81 m/s
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