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The quadratic equation 
has two roots 4a and 3a, where a is an integer. Which of the following is a possible value of 
has two roots 4a and 3a, where a is an integer. Which of the following is a possible value of - a)3721
- b)361
- c)427
- d)549
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The quadratic equation has two roots 4a and 3a, where a is an integer....
Given,
The quadratic equation x2 + bx + c = 0 has two roots 4a and 3a
7a = -b
12a2 = c
We have to find the value of
b2 + c = 49a2 + 12a2 = 61a2
Now lets verify the options
61a2 = 3721 ==> a = 7.8 which is not an integer
61a2 = 361 ==> a = 2.42 which is not an integer
61a2 = 427 ==> a = 2.64 which is not an integer
61a2 = 3721 ==> a = 3 which is an integer
The quadratic equation x2 + bx + c = 0 has two roots 4a and 3a
7a = -b
12a2 = c
We have to find the value of
b2 + c = 49a2 + 12a2 = 61a2
Now lets verify the options
61a2 = 3721 ==> a = 7.8 which is not an integer
61a2 = 361 ==> a = 2.42 which is not an integer
61a2 = 427 ==> a = 2.64 which is not an integer
61a2 = 3721 ==> a = 3 which is an integer
Most Upvoted Answer
The quadratic equation has two roots 4a and 3a, where a is an integer....
Roots are given as 4a and 3a
summation of root is given as -b/a which are coefficient in equation
so 7a =-b
multiplication of roots is given as c/a which is 12a²
now b²+c is 49a² +12a²=61a²
it is also given that a is an integer
now try from option
A) a²=3721/61=61; a²=61(not possible for a to be integer(
B) a²=361/61= around 6 so not possible
C)a²= 427/61= 7 so not possible
D) a²=549/61= 9 so a=3
so answer is D
summation of root is given as -b/a which are coefficient in equation
so 7a =-b
multiplication of roots is given as c/a which is 12a²
now b²+c is 49a² +12a²=61a²
it is also given that a is an integer
now try from option
A) a²=3721/61=61; a²=61(not possible for a to be integer(
B) a²=361/61= around 6 so not possible
C)a²= 427/61= 7 so not possible
D) a²=549/61= 9 so a=3
so answer is D
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Community Answer
The quadratic equation has two roots 4a and 3a, where a is an integer....
Given,
The quadratic equation x2 + bx + c = 0 has two roots 4a and 3a
7a = -b
12a2 = c
We have to find the value of
b2 + c = 49a2 + 12a2 = 61a2
Now lets verify the options
61a2 = 3721 ==> a = 7.8 which is not an integer
61a2 = 361 ==> a = 2.42 which is not an integer
61a2 = 427 ==> a = 2.64 which is not an integer
61a2 = 3721 ==> a = 3 which is an integer
The quadratic equation x2 + bx + c = 0 has two roots 4a and 3a
7a = -b
12a2 = c
We have to find the value of
b2 + c = 49a2 + 12a2 = 61a2
Now lets verify the options
61a2 = 3721 ==> a = 7.8 which is not an integer
61a2 = 361 ==> a = 2.42 which is not an integer
61a2 = 427 ==> a = 2.64 which is not an integer
61a2 = 3721 ==> a = 3 which is an integer
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The quadratic equation has two roots 4a and 3a, where a is an integer. Which of the following is a possible value ofa)3721b)361c)427d)549Correct answer is option 'D'. Can you explain this answer?
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