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A particle is moving with a uniform speed v in a circular path of radius r with the centre at O. When the particle moves from a point P to Q on the circle such that ∠POQ =  θ, then the magnitude of the change in velocity is
  • a)
    2v sin (2θ)
  • b)
    zero
  • c)
    2v sin (θ/2)
  • d)
    2v cos (θ/2)
Correct answer is option 'C'. Can you explain this answer?
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A particle is moving with a uniform speed v in a circular path of radi...
PQ is a diameter, the angle subtended by PQ at the center O is 90 degrees.
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A particle is moving with a uniform speed v in a circular path of radius r with the centre at O. When the particle moves from a point P to Q on the circle such that ∠POQ = θ, then the magnitude of the change in velocity isa)2v sin (2θ)b)zeroc)2v sin (θ/2)d)2v cos(θ/2)Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle is moving with a uniform speed v in a circular path of radius r with the centre at O. When the particle moves from a point P to Q on the circle such that ∠POQ = θ, then the magnitude of the change in velocity isa)2v sin (2θ)b)zeroc)2v sin (θ/2)d)2v cos(θ/2)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is moving with a uniform speed v in a circular path of radius r with the centre at O. When the particle moves from a point P to Q on the circle such that ∠POQ = θ, then the magnitude of the change in velocity isa)2v sin (2θ)b)zeroc)2v sin (θ/2)d)2v cos(θ/2)Correct answer is option 'C'. Can you explain this answer?.
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