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An objective type test paper has 5 questions. Out of these 5 questions, 3 questions have four options each (A, B, C, D) with one option being the correct answer. The other 2 questions have two options each, namely True and False. A candidate randomly ticks the options. Then the probability that he/she will tick the correct option in at least four questions, is
  • a)
     5/32
  • b)
     3/128 
  • c)
     3/256
  • d)
    3/64
Correct answer is option 'D'. Can you explain this answer?
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An objective type test paper has 5 questions. Out of these 5 questions...
n(S) = 43. 22, n(e) = (3C1 .3 + 2C1. 1) + 1
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An objective type test paper has 5 questions. Out of these 5 questions...
Objective Type Test Paper

Objective type test papers often consist of multiple-choice questions with various options. In this particular scenario, we have a test paper with 5 questions. Let's break down the question and calculate the probability of ticking the correct option in at least four questions.

Question Breakdown:

Out of the 5 questions:
- 3 questions have four options each (A, B, C, D), with one correct option.
- 2 questions have two options each, namely True and False.

Calculating the Probability:

To calculate the probability of ticking the correct option in at least four questions, we need to consider the different combinations in which this can occur.

Case 1: Ticking all three questions with four options correctly
In this case, the probability of ticking all three questions correctly is (1/4) * (1/4) * (1/4) = 1/64.

Case 2: Ticking two questions with four options correctly and one True/False question correctly
There are three ways to choose the two questions with four options and one question with True/False. The probability for each combination is:
- (1/4) * (1/4) * (1/2) = 1/32 (for two four-option questions and one True/False question)
- (1/4) * (1/4) * (1/2) = 1/32 (for two four-option questions and one True/False question)
- (1/4) * (1/4) * (1/2) = 1/32 (for two four-option questions and one True/False question)

So, the total probability for this case is 1/32 + 1/32 + 1/32 = 3/32.

Case 3: Ticking one question with four options correctly and both True/False questions correctly
There are three ways to choose the one question with four options and two questions with True/False. The probability for each combination is:
- (1/4) * (1/2) * (1/2) = 1/16 (for one four-option question and two True/False questions)
- (1/4) * (1/2) * (1/2) = 1/16 (for one four-option question and two True/False questions)
- (1/4) * (1/2) * (1/2) = 1/16 (for one four-option question and two True/False questions)

So, the total probability for this case is 1/16 + 1/16 + 1/16 = 3/16.

Case 4: Ticking all three True/False questions correctly
The probability of ticking all three True/False questions correctly is (1/2) * (1/2) * (1/2) = 1/8.

Calculating the Total Probability:

To calculate the total probability of ticking the correct option in at least four questions, we add up the probabilities from all the cases:

1/64 + 3/32 + 3/16 + 1/8 = 1/64 + 6/64 + 12/64 +
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