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[Co(NH₃)₄(NO₂)₂]Cl exhibits
  • a)
    linkage isomerism, geometrical isomerism and optical isomerism
  • b)
    linkage isomerism, ionization isomerism and optical isomerism
  • c)
    linkage isomerism, ionization isomerism and geometrical isomerism
  • d)
    ionization isomerism, geometrical isomerism and optical isomerism
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
[Co(NH₃)₄(NO₂)₂]Cl exhibitsa)linkage isomerism, geometrical isomerism ...
[Co(NH₃)₄(NO₂)₂]Cl is a coordination compound containing a central cobalt ion coordinated to four ammonia ligands and two nitrite ligands. The compound also has a chloride ion as an anion. It exhibits linkage isomerism, ionization isomerism, and geometrical isomerism.

Explanation:

1. Linkage Isomerism:
Linkage isomerism occurs when a ligand can coordinate to the central metal ion through different atoms. In this compound, the nitrite ligand (NO₂⁻) can coordinate to the cobalt ion through either the nitrogen atom (N-nitrito) or the oxygen atom (O-nitrito). Therefore, it exhibits linkage isomerism.

2. Ionization Isomerism:
Ionization isomerism occurs when there is an exchange of anionic and cationic ligands between the coordination sphere and the counter ion. In this compound, the chloride ion (Cl⁻) can be exchanged with the coordinated nitrite ligands (NO₂⁻), resulting in the formation of [Co(NH₃)₄Cl₂]NO₂. Therefore, it exhibits ionization isomerism.

3. Geometrical Isomerism:
Geometrical isomerism occurs when different spatial arrangements of ligands are possible around the central metal ion. In this compound, the coordination number of the cobalt ion is 6, and it has two different types of ligands, ammonia (NH₃) and nitrite (NO₂⁻). Therefore, it exhibits geometrical isomerism. The possible geometric isomers are cis and trans, depending on the arrangement of the two nitrite ligands.

4. Optical Isomerism:
Optical isomerism occurs when a compound is chiral and exists in two non-superimposable mirror-image forms (enantiomers). However, in this compound, there is no chiral center present, and therefore it does not exhibit optical isomerism.

Hence, the correct answer is option 'C', which includes linkage isomerism, ionization isomerism, and geometrical isomerism.
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[Co(NH₃)₄(NO₂)₂]Cl exhibitsa)linkage isomerism, geometrical isomerism and optical isomerismb)linkage isomerism, ionization isomerism and optical isomerismc)linkage isomerism, ionization isomerism and geometrical isomerismd)ionization isomerism, geometrical isomerism and optical isomerismCorrect answer is option 'C'. Can you explain this answer?
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