Class 11 Chemistry

Introduction to C3H6Br2
C3H6Br2 is the chemical formula for 1,2-dibromopropane. It is an organic compound belonging to the class of haloalkanes. The molecule consists of three carbon atoms, six hydrogen atoms, and two bromine atoms.

Physical Properties of C3H6Br2
- Molecular weight: 201.88 g/mol
- Appearance: Clear, colorless liquid
- Boiling point: 96-99°C
- Melting point: -95°C
- Density: 1.81 g/cm³

Chemical Reactions of C3H6Br2
1. Hydrolysis
- C3H6Br2 can undergo hydrolysis in the presence of a strong base or water to form an alcohol and a bromide ion.
- The reaction is as follows:
C3H6Br2 + H2O → C3H7OH + Br^-

2. Elimination Reaction
- C3H6Br2 can undergo elimination reactions to form an alkene.
- In the presence of a strong base like sodium ethoxide (NaOC2H5) or potassium tert-butoxide (KOtBu), 1,2-dibromopropane can eliminate a hydrogen atom from one carbon and a bromine atom from the adjacent carbon, resulting in the formation of propene.
- The reaction is as follows:
C3H6Br2 + KOtBu → C3H6 + KBr + HBr

3. Nucleophilic Substitution Reactions
- C3H6Br2 can undergo nucleophilic substitution reactions with various nucleophiles.
- In the presence of a nucleophile such as hydroxide ion (OH^-), thiourea (CS(NH2)2), or ammonia (NH3), 1,2-dibromopropane can undergo substitution reactions to form different compounds depending on the nucleophile used.
- For example, with hydroxide ion, the reaction is as follows:
C3H6Br2 + OH^- → C3H5OH + Br^-

Conclusion
C3H6Br2, or 1,2-dibromopropane, is an organic compound that can undergo various chemical reactions such as hydrolysis, elimination, and nucleophilic substitution. These reactions result in the formation of different compounds, including alcohols and alkene. Understanding the reactivity of C3H6Br2 is essential in organic chemistry as it allows for the synthesis of new compounds and the understanding of reaction mechanisms.