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Sunil wants to spend Rs. 200 on two types of sweets, costing Rs. 7 and Rs. 10 respectively. What is the maximum number of sweets he can get so that no money is left over?
- a)25
- b)26
- c)27
- d)28
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Sunil wants to spend Rs. 200 on two types of sweets, costing Rs. 7 and...
Let Sunil get x number of Rs. 7 sweet and y number of Rs. 10 sweet;
From the given condition;
7x + 10y = 200
The integer values of x and y that can satisfy this equation are;
7x + 10y = 200
The integer values of x and y that can satisfy this equation are;
Either x = 10 and y = 13 or x = 20 and y = 6
Since we want maximum value of (x + y), ‘x = 20 and y = 6’ will suffice.
∴ Maximum number of sweets = 20 + 6 = 26
Since we want maximum value of (x + y), ‘x = 20 and y = 6’ will suffice.
∴ Maximum number of sweets = 20 + 6 = 26
Most Upvoted Answer
Sunil wants to spend Rs. 200 on two types of sweets, costing Rs. 7 and...
Explanation:
Given:
- Cost of first type of sweets = Rs. 7
- Cost of second type of sweets = Rs. 10
- Total amount to be spent = Rs. 200
Let's assume:
- Number of first type of sweets bought = x
- Number of second type of sweets bought = y
Formulating the equation:
- 7x + 10y = 200
Finding the maximum number of sweets:
- To maximize the number of sweets bought, we need to find the maximum value of x and y that satisfies the equation above.
Using trial and error method:
- By trying different values of x and solving for y, we find that x = 26 and y = 6 satisfies the equation.
- Therefore, the maximum number of sweets Sunil can buy without any money left over is 26 + 6 = 32.
Therefore, the correct answer is option B) 26.
Given:
- Cost of first type of sweets = Rs. 7
- Cost of second type of sweets = Rs. 10
- Total amount to be spent = Rs. 200
Let's assume:
- Number of first type of sweets bought = x
- Number of second type of sweets bought = y
Formulating the equation:
- 7x + 10y = 200
Finding the maximum number of sweets:
- To maximize the number of sweets bought, we need to find the maximum value of x and y that satisfies the equation above.
Using trial and error method:
- By trying different values of x and solving for y, we find that x = 26 and y = 6 satisfies the equation.
- Therefore, the maximum number of sweets Sunil can buy without any money left over is 26 + 6 = 32.
Therefore, the correct answer is option B) 26.
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Sunil wants to spend Rs. 200 on two types of sweets, costing Rs. 7 and Rs. 10 respectively. What is the maximum number of sweets he can get so that no money is left over?a)25b)26c)27d)28Correct answer is option 'B'. Can you explain this answer?
Question Description
Sunil wants to spend Rs. 200 on two types of sweets, costing Rs. 7 and Rs. 10 respectively. What is the maximum number of sweets he can get so that no money is left over?a)25b)26c)27d)28Correct answer is option 'B'. Can you explain this answer? for Defence 2024 is part of Defence preparation. The Question and answers have been prepared according to the Defence exam syllabus. Information about Sunil wants to spend Rs. 200 on two types of sweets, costing Rs. 7 and Rs. 10 respectively. What is the maximum number of sweets he can get so that no money is left over?a)25b)26c)27d)28Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Defence 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sunil wants to spend Rs. 200 on two types of sweets, costing Rs. 7 and Rs. 10 respectively. What is the maximum number of sweets he can get so that no money is left over?a)25b)26c)27d)28Correct answer is option 'B'. Can you explain this answer?.
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