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A band brake shown below absorbed 30KW when a drum rotates at 500rpm. Drum dia= 500mm, u =0.3 stress for band material= 80Mpa, band thickness = 3mm. Determine width of band?
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A band brake shown below absorbed 30KW when a drum rotates at 500rpm. ...
Calculation of Band Width for a Band Brake


Given Parameters:


  • Power = 30 KW

  • Drum Speed (N) = 500 rpm

  • Drum Diameter (D) = 500 mm

  • Coefficient of Friction (u) = 0.3

  • Stress for Band Material (σ) = 80 MPa

  • Band Thickness (t) = 3 mm



Formula:


  • Torque (T) = (Power * 60) / (2 * π * N)

  • Tension on Band (F) = T / (D / 2)

  • Band Width (B) = F / (σ * t * u)



Calculation:

First, we need to calculate the torque required to absorb the given power:


  • T = (30 * 1000 * 60) / (2 * π * 500) = 572.96 Nm


Next, we can calculate the tension on the band:


  • F = T / (D / 2) = 572.96 / 250 = 2.2918 kN


Finally, we can calculate the required band width:


  • B = F / (σ * t * u) = 2.2918 / (80 * 10^6 * 3 * 0.3) = 3.21 mm



Answer:

Therefore, the required band width for the given parameters is 3.21 mm.
Community Answer
A band brake shown below absorbed 30KW when a drum rotates at 500rpm. ...
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A band brake shown below absorbed 30KW when a drum rotates at 500rpm. Drum dia= 500mm, u =0.3 stress for band material= 80Mpa, band thickness = 3mm. Determine width of band?
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