The units digit of a two digit number is 3 and seven times the sum of ...
The number is 63. Because if we put 6 as on tens place then it will be 63. And 6+3=9. And 9*7 is also 63. And plz plz plz upvote....
The units digit of a two digit number is 3 and seven times the sum of ...
Problem Analysis:
Let's assume the two-digit number is represented by AB, where A is the tens digit and B is the units digit. We are given that the units digit is 3, so B = 3. We are also given that seven times the sum of the digits is equal to the number itself, so 7(A + B) = 10A + B.
Solution:
We need to find the value of A and B that satisfies both conditions.
Step 1: Substitute the value of B into the equation.
7(A + 3) = 10A + 3
Step 2: Simplify the equation.
7A + 21 = 10A + 3
Step 3: Subtract 7A from both sides of the equation.
21 = 3A + 3
Step 4: Subtract 3 from both sides of the equation.
18 = 3A
Step 5: Divide both sides of the equation by 3.
A = 6
Step 6: Substitute the value of A into the equation.
7(6 + 3) = 10(6) + 3
Step 7: Simplify the equation.
7(9) = 60 + 3
Step 8: Multiply and add.
63 = 63
Step 9: The equation is true, so the value of A = 6 and B = 3 satisfies the conditions.
Answer:
Therefore, the two-digit number is 63.