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A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)
- a)4.9
- b)5.0
- c)7.0
- d)10.0
Correct answer is option 'C'. Can you explain this answer?
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A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100...
Given information:
- Concentration of ammonium acetate solution = 0.1 M
- Volume of ammonium acetate solution = 100 ml
- Volume of water added = 100 ml
- pKa of acetic acid ≈ pKb of NH4OH
Calculating the moles of ammonium acetate:
- Moles of ammonium acetate = Concentration × Volume
- Moles of ammonium acetate = 0.1 M × 0.1 L
- Moles of ammonium acetate = 0.01 moles
Calculating the moles of acetic acid and ammonium hydroxide:
- Ammonium acetate dissociates into acetic acid and ammonium hydroxide in water.
- The molar ratio of acetic acid and ammonium hydroxide is 1:1.
- So, the moles of acetic acid and ammonium hydroxide will be equal.
Moles of acetic acid:
- Moles of acetic acid = 0.01 moles
Moles of ammonium hydroxide:
- Moles of ammonium hydroxide = 0.01 moles
Calculating the concentration of acetic acid and ammonium hydroxide:
- The total volume of the solution after dilution = Volume of ammonium acetate + Volume of water
- Total volume = 100 ml + 100 ml
- Total volume = 200 ml
Concentration of acetic acid:
- Concentration of acetic acid = Moles of acetic acid / Total volume
- Concentration of acetic acid = 0.01 moles / 0.2 L
- Concentration of acetic acid = 0.05 M
Concentration of ammonium hydroxide:
- Concentration of ammonium hydroxide = Moles of ammonium hydroxide / Total volume
- Concentration of ammonium hydroxide = 0.01 moles / 0.2 L
- Concentration of ammonium hydroxide = 0.05 M
Calculating the pH:
- Since the pKa of acetic acid is nearly equal to the pKb of NH4OH, the solution will be approximately neutral.
- At neutral pH, the concentration of H+ ions and OH- ions will be equal.
- Therefore, the pH will be 7.0.
Answer:
The pH of the resulting solution will be 7.0. (Option C)
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A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer?
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A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer?.
A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer?.
Solutions for A 100 ml 0.1 (M) solution of ammonium acetate is diluted by adding 100 ml of water. The pH of the resulting solution will be (pKa of acetic acid is nearly equal to pKb of NH4OH)a)4.9b)5.0c)7.0d)10.0Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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