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A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer?.

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Here you can find the meaning of A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A small coin of mass 40gis placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular accelerationα= 2 rad/s2. The coefficient of static friction between the coin and the disc isµs= 3/4 and coefficient of kinetic frictionµk= 0.5. The coin is placed at a distancer= 1mfrom the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is :a)0.3Nb)0.4Nc)0.5Nd)0.2NCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Physics tests.