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The sum of digits of a two-digit number is 13. When 45 is added to the number, the digits of the number are reversed. What is the actual number? (1) 31 (2) 85 (3) 94 (4) 58 (5) 49?
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The sum of digits of a two-digit number is 13. When 45 is added to the...
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The sum of digits of a two-digit number is 13. When 45 is added to the...

Understanding the Problem:
The problem states that the sum of the digits of a two-digit number is 13. When 45 is added to the number, the digits of the number are reversed. We need to find the actual number.

Approach:
Let's assume the two-digit number to be 10x + y, where x and y are the digits of the number.

Formulating Equations:
1. x + y = 13 (sum of the digits is 13)
2. 10x + y + 45 = 10y + x (when 45 is added, the digits are reversed)

Solving the Equations:
From equation 1, we get x = 13 - y
Substitute x in equation 2:
10(13 - y) + y + 45 = 10y + 13 - y
130 - 10y + y + 45 = 10y + 13 - y
130 + 45 = 10y + 13 - y
175 = 9y + 13
9y = 162
y = 18

Substitute y back into x + y = 13:
x + 18 = 13
x = -5

Since x and y are digits, x cannot be negative. Therefore, our assumption of x and y was incorrect.

Actual Number Calculation:
By trying the given options, we find that only option (5) 49 satisfies the conditions:
4 + 9 = 13
49 + 45 = 94 (digits reversed)

Therefore, the actual number is 49.
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The sum of digits of a two-digit number is 13. When 45 is added to the number, the digits of the number are reversed. What is the actual number? (1) 31 (2) 85 (3) 94 (4) 58 (5) 49?
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