Two blockAandBeach of massmare placed on a smooth horizontal surface. Two horizontal forceFand2Fare applied on both the blocksAandBrespectively as shown in figure. The blockAdoes not slide on block B. Then the normal reaction acting between the two blocks isnF: find the value ofn.Correct answer is '3'. Can you explain this answer?

Question

Answer

As block A does not slide on block B this means both blocks have the same acceleration along horizontal.

Net force on the system is 2F−F=F

Therefore, Acceleration is F/(m+m)=F/2m.

Now taking of individual blocks. Let Normal between block be N.

Block on right:

Along Horizontal:
2F−Nsin30=ma
⇒2F−m(F/2m)=N(1/2)
⇒3F/2=N/2
⇒N=3F

Just to check we can calculate N at block on right also;
Nsin30−F=ma
⇒F+m(F/2m)=N(1/2)
⇒3F/2=N/2
⇒N=3F

Answer

Acceleration of two mass system is a = F/2m leftward
FBD of block A

solving N = 3F
The correct answer is: 3

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