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Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10 m/s2. In this box if 1 kg body is suspended with a light string, the tension (in N) in the string in equilibrium position. (w.r.t.) experimenter will be (Take g = 10 m/s2)
Correct answer is '14.14'. Can you explain this answer?
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Verified Answer
Inside a horizontally moving box, an experimenter finds that the when ...
Acceleration of box = 10 m/s2
Inside the box force acting on bob are shown in the figure
Inside the box force acting on bob are shown in the figure
The correct answer is: 14.14
Most Upvoted Answer
Inside a horizontally moving box, an experimenter finds that the when ...
Analysis:
- The acceleration of the object on the table is given as 10m/s^2.
- The weight of the body is equal to its mass multiplied by the acceleration due to gravity (W = mg).
- In the equilibrium position, the tension in the string will be equal to the sum of the weight and the force required to provide the centripetal acceleration.
Solution:
- The weight of the 1kg body is equal to 1kg * 10m/s^2 = 10N.
- In equilibrium, the tension in the string will be equal to the centripetal force required to keep the body in a circular motion.
- Therefore, the tension T = (m * v^2) / r, where m is the mass of the body, v is the velocity of the body, and r is the radius of the circle.
- Since the body is in equilibrium, the centripetal force is equal to the weight of the body, so T = 10N.
- Using the formula for tension in terms of weight and centripetal force, we get T = √(10^2 + 10^2) = √200 ≈ 14.14N.
Therefore, the tension in the string in the equilibrium position with respect to the experimenter will be approximately 14.14N.
- The acceleration of the object on the table is given as 10m/s^2.
- The weight of the body is equal to its mass multiplied by the acceleration due to gravity (W = mg).
- In the equilibrium position, the tension in the string will be equal to the sum of the weight and the force required to provide the centripetal acceleration.
Solution:
- The weight of the 1kg body is equal to 1kg * 10m/s^2 = 10N.
- In equilibrium, the tension in the string will be equal to the centripetal force required to keep the body in a circular motion.
- Therefore, the tension T = (m * v^2) / r, where m is the mass of the body, v is the velocity of the body, and r is the radius of the circle.
- Since the body is in equilibrium, the centripetal force is equal to the weight of the body, so T = 10N.
- Using the formula for tension in terms of weight and centripetal force, we get T = √(10^2 + 10^2) = √200 ≈ 14.14N.
Therefore, the tension in the string in the equilibrium position with respect to the experimenter will be approximately 14.14N.
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Community Answer
Inside a horizontally moving box, an experimenter finds that the when ...
Acceleration of box = 10 m/s2
Inside the box force acting on bob are shown in the figure
Inside the box force acting on bob are shown in the figure
The correct answer is: 14.14
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Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer?
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Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer?.
Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer?.
Solutions for Inside a horizontally moving box, an experimenter finds that the when an object is placed on a smooth horizontal table and is released, it moves with an acceleration of 10m/s2. In this box if 1kgbody is suspended with a light string, the tension (inN) in the string in equilibrium position. (w.r.t.) experimenter will be (Takeg= 10m/s2)Correct answer is '14.14'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
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