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In the figure shown all the surfaces are smooth. All the blocks AB and C are movable, x-axis is horizontal and y-axis is vertical as shown. Just after the system is released from the position as shown.
Select one or more:
  • a)
    The acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater than gsinθ
  • b)
    Acceleration of ‘A’ relative to ground is in negative y-direction
  • c)
    The horizontal acceleration of ‘B’ relative to ground is in negative x-direction.
  • d)
    Acceleration of ‘A’ relative to B is in positive x-direction
Correct answer is option 'A,B,C,D'. Can you explain this answer?
Verified Answer
In the figure shown all the surfaces are smooth. All the blocksA,BandC...
There is no horizontal force on block A, therefore it does not move in x-direction, whereas there is net downwards force (mg – N) is acting on it, making its acceleration along negative y-direction.
Block B moves downwards as well as in negative x-direction. Downward acceleration of A and B will be equal due to constrain, thus w.r.t. BA moves in positive x-direction.
Due to the component of normal exerted by C on B, it moves in negative x-direction.
The force acting vertically downwards on block B are mg and NA (normal reaction due to block A). Hence the component of net force on block B along the inclined surface of B is greater than mg sin θ. Therefore the acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater than g sin θ.
The correct answers are: Acceleration of ‘A’ relative to ground is in negative y-direction, Acceleration of ‘A’ relative to B is in positive x-direction, The horizontal acceleration of ‘B’ relative to ground is in negative x-direction., The acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater than gsinθ
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Most Upvoted Answer
In the figure shown all the surfaces are smooth. All the blocksA,BandC...
There is no horizontal force on block A, therefore it does not move in x-direction, whereas there is net downwards force (mg – N) is acting on it, making its acceleration along negative y-direction.
Block B moves downwards as well as in negative x-direction. Downward acceleration of A and B will be equal due to constrain, thus w.r.t. BA moves in positive x-direction.
Due to the component of normal exerted by C on B, it moves in negative x-direction.
The force acting vertically downwards on block B are mg and NA (normal reaction due to block A). Hence the component of net force on block B along the inclined surface of B is greater than mg sin θ. Therefore the acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater than g sin θ.
The correct answers are: Acceleration of ‘A’ relative to ground is in negative y-direction, Acceleration of ‘A’ relative to B is in positive x-direction, The horizontal acceleration of ‘B’ relative to ground is in negative x-direction., The acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater than gsinθ
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In the figure shown all the surfaces are smooth. All the blocksA,BandCare movable,x-axis is horizontal andy-axis is vertical as shown. Just after the system is released from the position as shown.Select one or more:a)The acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater thangsinθb)Acceleration of ‘A’ relative to ground is in negativey-directionc)The horizontal acceleration of ‘B’ relative to ground is in negativex-direction.d)Acceleration of ‘A’ relative toBis in positive x-directionCorrect answer is option 'A,B,C,D'. Can you explain this answer?
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In the figure shown all the surfaces are smooth. All the blocksA,BandCare movable,x-axis is horizontal andy-axis is vertical as shown. Just after the system is released from the position as shown.Select one or more:a)The acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater thangsinθb)Acceleration of ‘A’ relative to ground is in negativey-directionc)The horizontal acceleration of ‘B’ relative to ground is in negativex-direction.d)Acceleration of ‘A’ relative toBis in positive x-directionCorrect answer is option 'A,B,C,D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In the figure shown all the surfaces are smooth. All the blocksA,BandCare movable,x-axis is horizontal andy-axis is vertical as shown. Just after the system is released from the position as shown.Select one or more:a)The acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater thangsinθb)Acceleration of ‘A’ relative to ground is in negativey-directionc)The horizontal acceleration of ‘B’ relative to ground is in negativex-direction.d)Acceleration of ‘A’ relative toBis in positive x-directionCorrect answer is option 'A,B,C,D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the figure shown all the surfaces are smooth. All the blocksA,BandCare movable,x-axis is horizontal andy-axis is vertical as shown. Just after the system is released from the position as shown.Select one or more:a)The acceleration of ‘B’ relative to ground directed along the inclined surface of ‘C’ is greater thangsinθb)Acceleration of ‘A’ relative to ground is in negativey-directionc)The horizontal acceleration of ‘B’ relative to ground is in negativex-direction.d)Acceleration of ‘A’ relative toBis in positive x-directionCorrect answer is option 'A,B,C,D'. Can you explain this answer?.
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